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2 years ago

Where does diffusion occur in the excretory system

Physics

1 answer:

k0ka [10]2 years ago

6 0

Answer:

Diffusion of water, salts, and waste products occurs in the kidneys. Diffusion of calcium from food into cells occurs in the intestines. Molecules are not the only things that can diffuse. Heat from the body diffuses away in the form of sweat that evaporates.

Explanation:

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You might be interested in

Why do natural polymers not pose as much of an issue in landfills as synthetic polymers?

viva [34]

Answer:

Most polymers, including poly(ethene) and poly(propene) are not biodegradable . This means that microorganisms cannot break them down, so they: cause a litter problem if disposed of carelessly. last for many years in landfill sites.

Explanation:

8 0

2 years ago

An electron is trapped in an infinite square-well potential of width 0.6 nm. If the electron is initially in the n = 4 state, wh

grandymaker [24]

Answer:

E₁ = 1.042 eV

E₄₋₃= 7.29 eV

E₄₋₂= 12.50 eV

E₄₋₁= 15.63 eV

E₃₋₂= 5.21eV

E₃₋₁= 8.34eV

E₂₋₁= 3.13eV

Explanation:

The energy in an infinite square-well potential is giving by:

$E = \frac {h^{2} n^{2}}{8mL^{2}}$

where, h: Planck constant = 6.62x10⁻³⁴J.s, n: is the energy state, m: mass of the electron and L: widht of the square-well potential

The energy of the electron in the ground state, n = 1, is:

$E_{1} = \frac {(6.62 \cdot 10^{-34})^{2} (1)^{2}}{(8) (9.11 \cdot 10^{-31}) (0.6 \cdot 10^{-9} m)^{2}}$

$E_{1} = 1.67 \cdot 10^{-19} J = 1.042 eV$

The photon energies that are emitted as the electron jumps to the ground state is the difference between the states:

$E_{\Delta n} = \Delta n^{2} E_{1}$

$E_{(4 - 3)} = (4^{2} - 3^{2}) 1.042 eV = 7.29eV$

$E_{(4 - 2)} = (4^{2} - 2^{2}) 1.042 eV = 12.50eV$

$E_{(4 - 1)} = (4^{2} - 1^{2}) 1.042 eV = 15.63eV$

$E_{(3 - 2)} = (3^{2} - 2^{2}) 1.042 eV = 5.21eV$

$E_{(3 - 1)} = (3^{2} - 1^{2}) 1.042 eV = 8.34eV$

$E_{(2 - 1)} = (2^{2} - 1^{2}) 1.042 eV = 3.13eV$

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7 0

2 years ago

A stockroom worker pushes a box with mass 11.2 kg on a horizontal surface with constant speed of 3.50m/s. The coefficient of kin

stellarik [79]

Answer:

3.125 m

Explanation:

We are given that

Mass of box=m=11.2 kg

Speed of box=u=3.5m/s

Coefficient of kinetic friction= $\mu_k=0.2$

Final velocity,v=0

a.We have to find the horizontal force applied by worker to maintain the motion.

According to question

Horizontal force=F= $f=\mu_kmg$

$g=9.8m/s^2$

Substitute the values

Horizontal force= $F=0.2\times 11.2\times 9.8=21.95 N$

b.According to work-energy theorem

$W=\frac{1}{2}mv^2-\frac{1}{2}mu^2$

$-\mu mg s=\frac{1}{2}(11.2)(0)^2-\frac{1}[2}(11.20)(3.5)^2$

$-\mu mg s=-\frac{1}{2}(11.2)(3.5)^2$

$0.2\times (11.2)\times 9.8\times s=\frac{1}{2}(11.2)(3.5)^2$

$s=\frac{11.2\times (3.5)^2}{2\times 0.2\times 11.2\times 9.8}$

$s=3.125 m$

Hence, the box slide before coming to rest=3.125 m

4 0

3 years ago

Jose is loading his luggage into his car so that he can go to visit his grandmother. He lifts his suitcase up a 10 m staircase i

maxonik [38]

Answer:

The work done on the suitcase is, W = 600 J

Explanation:

Given,

The average force exerted by Jose on his suitcase, F = 60 N

Jose carried the suitcase to a distance, S = 10 m

The work done on the suitcase is given by the relation

W = F x S

Substituting the given values in the above equation,

W = 60 N x 10 m

= 600 J

Hence, the work done on the suitcase is, W = 600 J

3 0

2 years ago

What does an atomic nucleus give off a particle?

____ [38]

The correct answer is answer choice B.

5 0

3 years ago