After the collision the magnitude of the momentum of the system is Mv
Given:
mass of 1st object = M
speed of 1st object = v
mass of 2nd object = M
speed of 2nd object = 0
To Find:
magnitude of the momentum after collision
Solution: Product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton's second law of motion states that the time rate of change of momentum is equal to the force acting on the particle.
Applying conservation of linear momentum
Mv + M(0) = 2MV
Mv = 2MV
V = v/2
So, after collision momentum is
p = 2MV = 2xMxv/2 = Mv
So, after collision momentum is Mv
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Answer:
Magnitude of Vector = 79.3
Explanation:
When a vector is resolved into its rectangular components, it forms two vector components. These components are named as x-component and y-component, they are calculated by the following formulae:
x-component of vector = (Magnitude of Vector)(Cos θ)
y-component of vector = (Magnitude of Vector)(Sin θ)
where,
θ = angle of the vector with x-axis = 27°
Therefore, using the values in the equation of y-component, we get:
36 = (Magnitude of Vector)(Sin 27°)
Magnitude of Vector = 36/Sin 27°
<u>Magnitude of Vector = 79.3</u>
Answer:4
Explanation:
Given
Frequency of beats is 3 beats per second
Frequency of first tuning fork is 
Beat frequency is difference in the frequency of tuning forks i.e.
either 
or 
so 
or
so there is not enough information given to decide.
(d) Acceleration is a vector quantity
