Ask question

Ask question

All categories

3 years ago

6

wave absorption results in some of the wave's energy being converted into thermal energy. Describe an example of a time you've e

xperienced this type of wave behavior and energy conservation with a light wave and a second example with a sound wave

1 answer:

FinnZ [79.3K]3 years ago

5 0

Answer:

,,,,,,

Explanation:

m jkg yrfyuih iopoj kpoohjkbhj huiph i

You might be interested in

A bird flies directly into the windshield of a moving car. How does the FORCE exerted on the car compare to the FORCE exerted on

Anarel [89]

Answer:

b

Explanation:

7 0

3 years ago

Heat transfer by radiation depends on ____

notsponge [240]

Answer:

Infrared

Explanation:

This is the electromagnetic spectrum just above the visible light spectrum with higher energy (and higher frequency). This electromagnetic radiation is responsible for feeling the heat when you place your hand close to the side of a fire. It is also harnessed in night vision where bodies that emit some form of heat are visible due to their emission of IR.

5 0

3 years ago

Two automobiles are 150 kilometers apart and traveling toward each other. One automobile

Vladimir79 [104]

Their relative speed is the sum of 60 and 40 or 100km/hr. They will travel the 150km in 1.5 hrs. When two object approach each other, the closing speed is just the sum of the speeds, therefore, the closing speed is your case is 100kph. So they will meet in 1.5 hours.

8 0

3 years ago

What kind of deformation does a cube of Jell-O exhibit when it jiggles?

nadya68 [22]

It depends on chemistry... A physical deformation to the Jell-O.

3 0

4 years ago

Two identical loudspeakers are placed on a wall 1.00 m apart. A listener stands 4.00 m from the wall directly in front of one of

natita [175]

Answer:

The phase difference is 0.659 rad.

Explanation:

Given that,

Distance between two identical loudspeakers d= 1.00 m

Distance between speakers and listener r= 4.00 m

Frequency = 300 Hz

Suppose we need to find the phase difference in radian between the waves from the speakers when they reach the observer

We need to calculate the r'

Using Pythagorean theorem

$r'=\sqrt{d^2+r^2}$

Where, d = distance between two identical loudspeakers

r = distance between speakers and listener

Put the value into the formula

$r'=\sqrt{(1.00)^2+(4.00)^2}$

$r'=\sqrt{1.00+16.00}$

$r'=4.12\ m$

We need to calculate the path difference

Using formula of path difference

$|r'-r|=4.12-4.00$

$|r'-r|=0.12\ m$

We need to calculate the wavelength

Using formula of wavelength

$\lambda=\dfrac{v}{f}$

Where, v = speed of sound

f = frequency

Put the value into the formula

$\lambda=\dfrac{343}{300}$

$\lambda=1.143\ m$

We need to calculate the phase difference

Using formula of phase difference

$\phi=\dfrac{2\pi\times|r'-r| }{\lambda}$

$\phi=\dfrac{2\pi\times0.12}{1.143}$

$\phi=0.659\ rad$

Hence, The phase difference is 0.659 rad.

7 0

4 years ago