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3 years ago

6

A swimming pool had 2.52.52, point, 5 million liters of water in it. Some water evaporated, and then the pool only had 222 milli

on liters of water in it.What percent of the water evaporated?

2 answers:

Rom4ik [11]3 years ago

6 0

20%

Hope it's helpfull!

gizmo_the_mogwai [7]3 years ago

4 0

Answer:

20%

Step-by-step explanation:

x = ( $\frac{2}{2.5}$ ) * 100% = 80%

x = 20%

Therefore the answer is 20%

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2 years ago

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Answer:

The minimum value for $f(x) = 0.15(x + 1)^2 - 3$ is $-3$ .

Step-by-step explanation:

Given function is $f(x) = 0.15(x + 1)^2 - 3$

We need to find the maximum value or the minimum value for the function.

Now, differentiate $f(x) = 0.15(x + 1)^2 - 3$ w.r.t $x$ .

$f'(x) =\frac{d}{dx}(0.15(x + 1)^2 - 3)\\f'(x)=\frac{d}{dx}(0.15(x+1)^2-\frac{d}{dx}(3)\\$

$f'(x)=2\times 0.15(x+1)\frac{d}{dx}(x+1)-0\\f'(x)=0.3(x+1)(1)\\f'(x)=0.3(x+1)$

Now, we will equate $f'(x)=0$ to find critical point.

$0.3(x+1)=0\\x=-1$

Plug this critical point in to the function $f(x) = 0.15(x + 1)^2 - 3$ we get,

$f(-1) = 0.15(-1 + 1)^2 - 3\\f(-1)=-3$

Also, $f''(x)=0.3$ which is positive, We have minimum value.

So, the minimum value for $f(x) = 0.15(x + 1)^2 - 3$ is $-3$ .

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