I know this is kinda late, but...
You can solve this easily as long as you remember how to find the volume of a cube. v=a^3, when a means length. The length is 1/2 cm, or .5 cm.
So, v+.5^3, which equals .125 cm. Each cube has a that volume. Now, multiply that by how many actual cubes there are, 96.
96 * .125 = 12
The missing figure is attached
The value of a is
⇒ 2nd answer
Step-by-step explanation:
Let as revise the Pythagoras Theorem
In the right triangle ABC, where ∠B is a right angle (AC is the hypotenuse, Ab and BC are the legs of the right angle)
- (AC)² = (AB)² + (BC)²
- (AB)² = (AC)² - (BC)²
- (BC)² = (AC)² - (AB)²
If BD is drawn perpendicular to AC, we can use these rules
- (AB)² = AD × AC
- (BC)² = CD × AC
- (BD)² = AD × CD
- AB × BC = BD × AC
In Δ WYZ
∵ m∠WYZ = 90°
- By using Pythagoras Theorem
∴ (WZ)² = (WY)² + (YZ)²
∵ WY = 4 units
∵ YZ = 3 units
∵ WZ = c units
∴ c² = (4)² + (3)²
∴ c² = 16 + 9 = 25
- Take √ for both sides
∴ c = 5
In Δ XWZ
∵ m∠XWZ = 90°
∵ WY ⊥ XZ
- We can use the rule (WZ)² = ZY × ZX
∵ (WZ)² = ZY × ZX
∵ WZ = 5 units
∵ ZY = 3 units
∵ ZX = (3 + a) units
∴ (5)² = 3(3 + a)
∴ 25 = 9 + 3a
- Subtract 9 from both sides
∴ 16 = 3a
- Divide both sides by 3
∴ a = 
The value of a is 
Learn more:
You can learn more about the rules of the right triangle in brainly.com/question/14390928
#LearnwithBrainly
Answer: I believe its 24in not sure cause i got it on a not really reliable website
Step-by-step explanation:
Answer:
a ≤ 15
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
3(a - 4) ≤ 33
<u>Step 2: Solve for </u><em><u>a</u></em>
- Divide 3 on both sides: a - 4 ≤ 11
- Add 4 on both sides: a ≤ 15
Here we see that any value <em>a </em>less than or equal to 15 would work as a solution to the inequality.
Answer:
V = π × r² × h
Step-by-step explanation:
All you need to do is multiply the base times the height and since the base is a circle whose formula is π × r², we get π × r² × h.