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Anuta_ua [19.1K]
3 years ago
7

Pls helppppppppppppppppppppp

Mathematics
1 answer:
Julli [10]3 years ago
4 0

Answer:

10 2/3

Step-by-step explanation:

Multiply 4 and 2 and then multiply 2 and 4. If you do that then you get 8 8/3. You then just take the numerator and turn it into whole numbers to get 10 2/3.

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djverab [1.8K]
The prime factorization for 135 is 3,3,3, and 5.
6 0
3 years ago
Read 2 more answers
Help! Jeez these are hard.
Irina18 [472]

Answer:

option 2

Step-by-step explanation:

a colored in dot is less than or equal to or greater than or equal to while an uncolored dot is less then or greater than. arrow going left of the number is less than arrow going right is greater than. the problem is a is greater than 4/5 so an uncolored dot shout be on 4/5 going to the right

3 0
3 years ago
I don't understand please help
muminat
They will need 60 bags o sand because the new area is 13.5 feet by 18 feet. 
Just multiply everything by 1.5.
5 0
3 years ago
Rectangle LOSP is shown below. The lengths, in units, of some of the line segments are also shown. Line segments MQ and NR are p
Galina-37 [17]

Answer: c. OSRN

Step-by-step explanation:

Sides of similar shapes are proportional.

For Rectangle LOSP,

Length = LO = 4+6+8 = 18 units

Width = OS= 12 units

Here, \dfrac{18}{12}=\dfrac{3}{2}  [proportionality constant]

a. For Rectangle LMQP,

Length = MQ = 12 units

Width = LM = 4 units

Here, \dfrac{12}{4}=3\neq\dfrac32

LMQP is not similar to LOSP.

b. Similarly, for LNRP,

Width = LN= 4+6 = 10

length = NR = 12

\dfrac{12}{10}\neq\dfrac32

LNRP is not similar to LOSP.

c. For OSRN,

Length = OS = 12

Width = ON = 8

\dfrac{12}{8}=\dfrac32

OSRN is similar to LOSP.

d. For MNRQ,

Length= NR = 12

Width = MN = 6

\dfrac{12}{6}=2\neq\dfrac32

MNRQ  is not similar to LOSP.

Hence, the shape similar to rectangle LOSP is OSRN.

4 0
3 years ago
Una piscina rectangular de 15 m de largo por 9m de ancho está rodeada por un camino de cemento de ancho uniforme. ¿Si el área de
malfutka [58]

Answer:

El ancho del camino es 1.5 m.

Step-by-step explanation:

Una piscina rectangular posee 15 m de largo por 9 m de ancho.

El área de un rectángulo es igual a la base por la altura. Es decir, lado mayor por lado menor. Entonces el área de la piscina es 15 m* 9 m= 135 m²

La piscina está rodeada por un camino de cemento de ancho uniforme, al cual se denomina x y estará en unidades de metros (m). Entonces el largo de la piscina sumado al ancho a ambos lados de la piscina será 15 m + 2*x, mientras que el ancho de la piscina sumado al largo a ambos lados de la piscina es 9 m + 2*x. Entonces este área se puede expresar como

(15 m+2*x)*(9 m+ 2*x)

Entonces al área de la piscina sumado al camino se le resta el área de la piscina y da como resultado el área del camino, cuyo valor es 81 m²:

El área total - área de la piscina =  área del camino

(15 m +2*x)*(9 m+ 2*x) - 135 m²= 81 m²

Resolviendo:

15*9 m²+15*2*x + 9*2*x + 2*x*2*x - 135 m²= 81 m²

135 m² + 30*x + 18*x + 4*x² - 135 m²= 81 m²

48*x + 4*x² = 81 m²

48*x + 4*x² - 81 m²= 0

Siendo una ecuación cuadrática donde a= 4, b= 48 y c= -81, entonces:

\frac{-48+-\sqrt{48^{2}-4*4*(-81) } }{2*4}

Resolviendo:

\frac{-48+\sqrt{48^{2}-4*4*(-81) } }{2*4}= 1.5

\frac{-48-\sqrt{48^{2}-4*4*(-81) } }{2*4}= -13.5

Como las distancias solo pueden ser positivas, entonces <u><em>el ancho del camino es 1.5 m.</em></u>

En la imagen adjunta se puede observar un gráfico de la piscina más el camino

5 0
3 years ago
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