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Anuta_ua [19.1K]
3 years ago
7

Pls helppppppppppppppppppppp

Mathematics
1 answer:
Julli [10]3 years ago
4 0

Answer:

10 2/3

Step-by-step explanation:

Multiply 4 and 2 and then multiply 2 and 4. If you do that then you get 8 8/3. You then just take the numerator and turn it into whole numbers to get 10 2/3.

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Which confidence level would produce the widest interval when estimating the mean of a population based on the mean and standard
Dvinal [7]
<h3>Answer:  A) 99%</h3>

Explanation:

The larger the confidence level, the wider the confidence interval gets. Choice A provides the largest such confidence level.

It's like trying to catch an elusive fish. The wider the net, the more confident that you are likely to catch the fish. The size of the net can be a sort of measure of the confidence level.

4 0
2 years ago
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Is this correct ? Or would the angle be considered an acute angle
tino4ka555 [31]

Answer:

correct

Step-by-step explanation:

i think correct,but maybe i am wrong

6 0
3 years ago
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In order to solve the following system of equations by addition, which of the
Pavlova-9 [17]

Answer:

Multiply the top equation by -3 and the bottom equation by 2

Step-by-step explanation:

Given <u>system of equations</u>:

\begin{cases}4x-2y=7\\3x-3y=15 \end{cases}

To solve the given system of equations by addition, make one of the variables in both equations <u>sum to zero</u>.  To do this, the chosen variable must have the <u>same coefficient</u>, but it should be <u>negative</u> in one equation and <u>positive</u> in the other, so that when the two equations are added together, the variable is <u>eliminated</u>.

<u>To eliminate the </u><u>variable y</u>:

Multiply the top equation by -3 to make the coefficient of the y variable 6:

\implies -3(4x-2y=7) \implies -12x+6y=-21

Multiply the bottom equation by 2 to make the coefficient of the y variable -6:

\implies 2(3x-3y=15) \implies 6x-6y=30

Add the two equations together to <u>eliminate y</u>:

\begin{array}{l r r}& -12x+6y= &-21\\+ & 6x-6y= & 30\\\cline{1-3}& -6x\phantom{))))))} = & 9\end{array}

<u>Solve</u> for x:

\implies -6x=9

\implies x=-\dfrac{9}{6}=-\dfrac{3}{2}

<u>Substitute</u> the found value of x into one of the equations and <u>solve for y</u>:

\implies 3\left(-\dfrac{3}{2}\right)-3y=15

\implies -\dfrac{9}{2}-3y=15

\implies -3y=\dfrac{39}{2}

\implies y=-\dfrac{39}{2 \cdot 3}

\implies y=-\dfrac{13}{2}

Learn more about systems of equations here:

brainly.com/question/27868564

brainly.com/question/27520807

3 0
1 year ago
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The graph of y=f(x) is the solid black graph below. Which function represents the dotted graph?
Fed [463]

Answer:   y = f(x - 4) - 1, lower left corner

=============================================================

Explanation:

Let's focus on only the left-most points of each curve

For the black semicircle, the left-most point is located at (-7,0). The corresponding point on the red semicircle is at (-3,-1)

To go from (-7,0) to (-3,-1), we will do two things

  • Shift 4 units to the right
  • Shift 1 unit down

This can be done in any order. The action of "shift 4 units to the right" is effectively the same as shifting the xy axis 4 units to the left while keeping the curves fixed in place. This gives the illusion of movement. When we shift 4 the xy axis 4 units to the left, we're replacing each x input with x-4 as the new input.

In short, we go from f(x) to f(x-4). This is why we have this opposite motion going on.

The up and down motion is fairly straight forward. To shift 1 unit down, we subtract off 1. This is to subtract 1 from the y coordinate.

Overall, we go from y = f(x) to y = f(x - 4) - 1

Applying this transformation will move (-7,0) to (-3,-1) as described above. It will also move every other point on the black curve to their new corresponding location on the red curve.

3 0
3 years ago
If one root of the equation is 4x^2- 2x+p-4 be the reciprocal of other. then find the value of p​
SashulF [63]

Answer:

p = 8

Step-by-step explanation:

Let one root of the eqn. be alpha . Other root is 1/alpha .

We know that product of both roots of an quadratic eqn. is c/a where "c" is the co-efficient of the constant  & "a" is the co-efficient of x^2.

Here "c" is p-4 & "a" is 4. And the product of roots is 1 ( ∵ prdouct of a number and its reciprocal is 1 )

\frac{c}{a} = 1\\=> \frac{p - 4}{4} = 1\\=> p - 4 = 4\\=> p = 4 + 4 = 8

5 0
3 years ago
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