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docker41 [41]
3 years ago
10

If the area of a square is 100cm2, then what is its perimeter?

Mathematics
1 answer:
Vinil7 [7]3 years ago
6 0

Answer:

40cm

Step-by-step explanation:

A=s*s

A=10*10

A=100 cm^2

P=4*s

P=4*10

P=40 cm

"s" represents side

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It is given that AB is parallel to CD and points E, G, H, and F are collinear. The measure of ZEGF is 180°, by the definition of
alex41 [277]

The completed statement filled in with the correct option is presented as follows;

It is given that AB is parallel to CD and points, E, G, H, and F are collinear. The measure of ‹EGF is 180° by the definition of a straight angle. ‹AGE and ‹AGF are adjacent, so the measure of ‹AGE plus the measure of ‹AGF equals the measure of angle ‹EGF. It can be said that the measure of ‹AGE plus the measure of ‹AGF equals 180°. <u>‹CHE and ‹AG</u><u>F</u><u> are same side interior angles</u>, so the measure of angle ‹CHE plus the measure of angle ‹AGF equals 180°.

Substituting once again means that the measure of ‹AGE plus the measure of angle ‹AGF equals the measure of angle ‹CHE plus the measure of ‹AGF. The measure of angle ‹AGE is equal to the measure of ‹CHE <u>u</u><u>sing the </u><u>Subtraction</u><u> </u><u>P</u><u>roperty of </u><u>E</u><u>quality</u>. Finally, by the definition of congruency, ‹AGE is congruent to ‹CHE

The correct option is therefore;

  • ‹CHE and ‹AGE are same side interior angles; using the Subtraction Property of Equality

<h3>What relationships between angles formed by parallel lines can be used to complete the paragraph?</h3>

Angles, ‹CHE and ‹AGF are angles formed on the same side of the common transversal, EF, and are formed on the interior part of AB and CD.

Given that ‹CHE and ‹AGF are both on the line FGHE, and together with ‹CHF and ‹AGE form two linear pair angles, ‹CHE and ‹AGF are supplementary angles and add up to 180°.

According to the substitution property of equality, both sides of an equation remain equal following the subtraction of the same quantity from both sides.

Given that we have:

‹AGE + ‹AGF = ‹CHE + ‹AGF

Subtracting ‹AGF from both sides gives;

‹AGE = ‹CHE (subtraction property of equality)

Learn more about the angles formed by parallel lines here:

brainly.com/question/17430387

#SPJ1

3 0
1 year ago
You and two friends (Adam and Alana) will only play a game if it is fair for all three of you. The game your friend has proposed
scZoUnD [109]

Yes, the game was fair and no one had a better advantage.

4 0
3 years ago
Read 2 more answers
Look at the picture and plzz help me
Alisiya [41]

Answer:

a

Step-by-step explanation:

6 0
3 years ago
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The probability of passing the math class of Professor Jones is 64%, the probability of passing Professor Smith's physics class
alexgriva [62]

Answer:

The probability of using one or the other is 36%

Step-by-step explanation:

For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:

Probability of passing Professor Jones math class = 64% =0,64

P(J) = 0.64

Probabiliry of passing Professor Smith's physics class = 32% =0.32

P(S) = 0.32

Probability of passing both is = 30% = 0.30

P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram

We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing  Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:

P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%

If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.

5 0
3 years ago
Find the volume. Help asap. Please.
alexgriva [62]

Use the Pythagorean theorem to find the diameter:

Diameter = √(19.3^2 - 9.5^2)

Diameter = √(372.49 - 90.25)

Diameter = √282.24

Diameter = 16.8 m

Volume of a cylinder = PI x r^2 x h

r = 1/2 diameter = 16.8 /2 = 8.4

h = 9.5 m

Volume = PI x 8.4^2 x 9.5

= PI x 70.56 x 9.5

= PI x 670.32

In terms of PI volume = 670.32PI

As a decimal:

670.32 x 3.14 = 2104.8048 = 2100m^3 ( rounded to the nearest hundred)

5 0
3 years ago
Read 2 more answers
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