Answer:
<h3>The probability that the sum of Michelle's rolls is 4 is 0.083 </h3><h3>∴ P(A)=0.083 </h3>
Step-by-step explanation:
Given that Michelle is rolling two six-sided dice, numbered one through six.
<h3>To find the probability that the sum of her rolls is 4:</h3>

<h3>∴ n(s)=36</h3>
Let P(A) be the probability that the sum of her rolls is 4
Then the possible rolls with sums of 4 can be written as

<h3>n(A)=3</h3>
The probability that the sum of her rolls is 4 is given by



=0.083
<h3>∴ P(A)=0.083 </h3><h3>∴ the probability that the sum of Michelle's rolls is 4 is 0.083 </h3>
Answer:

Step-by-step explanation:
Factorise the denominators of both fractions
x² - 9 and x² - 4 are both differences of squares and factor as
x² - 9 = (x - 3)(x + 3) and x² - 4 = (x - 2)(x + 2), thus express as
× 
Cancel the factors (x + 3) and (x + 2) from the numerators/denominators of both fractions leaving

$37.95 x12= 455.4 so Kevin’s cellphone will cost 455.4 for the year
If you spent 80% that means you have 20% left, we'll use B as variable
20% x B = 12
0.20/0.20 x B = 12/0.20
B = 60
Mean = 5.555555555.....
median = 6
mode = 6
range= 1