The question is find the height of the tree, given that at two points 65 feet apart on the same side of the tree and in line with it, the angles of elevaton of the top of the tree are 21° 19' and 16°20'.
1) Convert the angles to decimal form:
19' * 1°/60' = 0.32° => 21° 19' = 21.32°
20' * 1°/60' = 0.33° => 16° 20' = 16.33°
2) Deduce the trigonometric ratios from the verbal information.
You can form a triangle with
- horizontal leg x + 65 feet
- elevation angle 16.33°
- vertical leg height of the tree, h
=> trigonometric ratio: tan (16.33) = h /( x + 65) => h = (x+65) * tan(16.33)
You can form a second triangle with:
- horizontal leg x
- elevation angle 21.32°
- vertical leg height of the tree, h
=> trigonometric ratio: tan(21.32) = h / x => h = x * tan(21.32)
Now equal the two expressions for h:
(x+65)*tan(16.33) = x*tan(21.32)
=> x*tan(16.33) + 65*tan(16.33) = x*tan(21.32)
=> x*tan(21.32) - x*tan(16.33) = 65*tan(16.33)
=> x = 65*tan(16.33) / [ tan(21.32) - tan(16.33) ] = 195.73 feet
=> h = 195.73 * tan(21.32) = 76.39 feet.
Answer: 76.39 feet
Answer:
Step-by-step explanation: you brine is smart use it
Hi!
<h3>To find the slope, use this formula</h3>
<h3>Put in the values</h3>
<h2>The slope is 1 </h2>
Hope this helps! :)
-Peredhel
All have 4 sides. That’s what I would put. Good luck and don’t copy links they’re most likely viruses
Answer:
The position P is:
ft <u><em> Remember that the position is a vector. Observe the attached image</em></u>
Step-by-step explanation:
The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity 
is:
Where 
is the initial height = 0 for this case
We know that the initial velocity is:
82 ft/sec at an angle of 58 ° with respect to the ground.
So:
ft/sec
ft/sec
Thus
The height after 2 sec is:
Then the equation that describes the horizontal position of the ball is
Where
for this case
ft / sec
ft/sec
So
After 2 seconds the horizontal distance reached by the ball is:
Finally the vector position P is:
ft
