Answer:
18
Step-by-step explanation:
brainliest plz
Answer:
probability that contractor 1,2 and 3 win is 33%,50% and 17% respectively
Step-by-step explanation:
assuming that there are no other contractors then:
probability that 1 , 2 or 3 win = 1
denoting as X= probability that contractor 3 wins , then assuming that only one wins , we have
probability that 1 , 2 or 3 win = 1
probability that contractor 1 wins + probability that contractor 2 wins + probability that contractor 3 wins = 1
2*P(X) + 3*P(X) + P(X) = 1
6*P(X) = 1
P(X) =1/6
then
-probability that contractor 1 wins = 2/6 (33%)
-probability that contractor 3 wins = 3/6 (50%)
-probability that contractor 3 wins = 1/6 (17%)
Answer:
2)A plane has length and width.
3)A plane extends infinitely in all directions
5)A plane is a flat surface.
Step-by-step explanation:
We can think of a plane as a line in space with no height, only length and width.
Yes, a plane is a two-dimensional surface, hence it has length and width.
2)A plane has length and width (TRUE)
The plane surface extends infinitely far, therefore it extends infinitely in all direction.
3)A plane extends infinitely in all directions (TRUE)
5)A plane is a flat surface(TRUE)
The correct options are 2,3 and 5.
See attachment
12 is 20% of 60 because 12/60 = 0.2.
Answer:
All non zero digits count in significant digits.
(a) is correct option.
Step-by-step explanation:
Given that,
1.4 has 2 significant digits.
We know that,
Significant digits :
All non zero digits count in significant digits.
All zero which is present in between two significant digits it is also significant.
Leading zero is not count as significant.
Trailing zero is count as significant.
We need to find 1.4 has 2 significant digits as a result of which rule
Using given rules
1.4 has 2 significant digits it is follows the rule of all non zero digits count in significant digits.
Hence, All non zero digits count in significant digits.
(a) is correct option.
