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balu736 [363]
2 years ago
10

Help please this question is so hard!

Mathematics
1 answer:
Nitella [24]2 years ago
6 0
So to solve this first you need to convert all the answers to decimals.
Site B 17/9 = 1.89 when you round up
Site D 4/3 = .75
Then look at all the numbers least to greatest.
D .75 m C 1.36 m A 1.60 m B 1.89 m
Answer D, C, A, B
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Crazy boy [7]

Answer:

Vertical shift down 4 units

Step-by-step explanation:

Vertical shift down 4 units

8 0
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Look at the stem-and-leaf plot.
cestrela7 [59]
The answer is c 10 #s are greater than 110
5 0
2 years ago
How to multiply numbers with exponets and different bases
o-na [289]
When the bases are diffenrent and the exponents of a and b are the same, we can multiply a and b first:
a n ⋅ b n = (a ⋅ b) n
Example:
32 ⋅ 42 = (3⋅4)2 = 122 = 12⋅12 = 144

When the bases and the exponents are different we have to calculate each exponent and then multiply:
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5 0
3 years ago
What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove
wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

  • \frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2

5b^3-10=6b^3-4b^2-10

\mathrm{Switch\:sides}

6b^3-4b^2-10=5b^3-10

6b^3-4b^2-10+10=5b^3-10+10

6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

b^3-4b^2=0

Using\:the\:Zero\:Factor\:Principle: if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

b=0,b-4=0

b=0,b=4

Therefore, the solutions are:

b=0,\:b=4

4 0
3 years ago
Read 2 more answers
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Slav-nsk [51]
You would get 2015.17568 as the interest rate i believe 
6 0
3 years ago
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