PLEASE HELP I WILL MARK BRAINLIEST!!!

Can someone please help me with math.

olasank [31]

Answer:

Its C

Step-by-step explanation:

3 0

3 years ago

A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature

Westkost [7]

Answer:

(a) The value of k is $\frac{1}{15}$ .

(b) The probability that at most three forms are required is 0.40.

(c) The probability that between two and four forms (inclusive) are required is 0.60.

(d) $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

Step-by-step explanation:

The random variable Y is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

$P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right$

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of k.

$\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}$

Thus, the value of k is $\frac{1}{15}$ .

(b)

Compute the value of P (Y ≤ 3) as follows:

$P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40$

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

$P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\ =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60$

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ to be the pmf of Y it has to satisfy the conditions:

$P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\$
$\sum P(y)=1$

Check condition 1:

$y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0$

Condition 1 is fulfilled.

Check condition 2:

$\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1$

Condition 2 is not satisfied.

Thus, $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

7 0

2 years ago

A coin will be tossed three times, and each toss will be recorded as heads (H) or tails (7). Give the sample space describing al

Fynjy0 [20]

Answer:

A). {HHH, HHT, HTH, THH, TTH,THT,HTT,TTT}

(B). {HHH, HHT, THH, THT}

Step-by-step explanation:

Given:

A coin is to be tossed three times and each tossed will be recorded as Head(H) and Tails(T).

To Find:

(a). Sample Space

(b). Event that the second toss is Heads

Explanation:

(A). Sample Space: When a coin is tossed 3 times

{HHH, HHT, HTH, THH, TTH,THT,HTT,TTT}

(B). Event that second toss is Head

{HHH, HHT, THH, THT}

6 0

3 years ago

What is the value of x? 1/3x-2/3=-18 ( please help it’s due tomorrow)

Nikolay [14]

X=56 is the answer :)

4 0

2 years ago

2. It’s time for Ronda to start repaying her student loans, which are amortized over the next 10 years. Her first month’s paymen

grigory [225]

Based on the amount that she paid in the first month, the amount Ronda will pay for the next month is $396.

When a loan is amortized, it means that one can pay it off by paying the same amount every period until they would have paid off both the loan and the associated interest.

The amortized amount contains:

A portion going towards the principal(debt )
A portion going towards the interest accumulated.

In conclusion, as the amount is the same every time, Ronda will have to pay the same amount of $396 the next month.

Find out more at brainly.com/question/12256592.

7 0

2 years ago