Answer:
v₂ = 22.5 m/s
Explanation:
Given that
For puck 1
m₁= 1 kg
u₁= 30 m/s
For puck 2
m₂= 1 kg
u₂= 0 m/s
After collision
Puck 1 have velocity v₁=7.5 m/s
Take puck 2 will have velocity v₂
From linear momentum conservation
P₁=P₂
m₁ u₁+m₂ u₂=m₁ v₁+m₂ v₂
1 x 30 + 1 x 0 = 1 x 7.5 + 1 x v₂
30 - 7.5 =v₂
v₂ = 22.5 m/s
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Answer:

Explanation:
We know that impedance of a RLC circuit is given by 
So
here R is resistance
is inductive reactance and
is capacitive reactance
To minimize the impedance
should be zero we know that 
So 


We know that 
So 

Where f is resonance frequency
To get this we need to know how long he was traveling. To know that we need to solve for the time it took for him to hit the ground. This is given by the vertical height he started at and the equation of motion for falling objects. The position function is
Y= -(9.8/2)t^2 + 50 = 0
t=3.19s
That's how long he's in the air. When he hits the ground he stops moving forward so this is also the amount of time he was moving at 100m/s horizontally. Now use speed distance relationship
X=vt
And solve for v
100m/3.19s = 31.35m/s