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kirill115 [55]
3 years ago
9

An ice skater is spinning on frictionless ice with her arms extended outward. She then pulls her arms in toward her body, reduci

ng her moment of inertia. Her angular momentum is conserved, so as she reduces her moment of inertia, her angular velocity increases and she spins faster. Compared to her initial rotational kinetic energy, her final rotational kinetic energy is _________
Physics
2 answers:
BigorU [14]3 years ago
5 0

Answer:

Rotational kinetic energy will Increase

Explanation:

Rotational kinetic energy KE is

KE = 1/2 x I x w^2

Where I is moment of inertia,

w is angular velocity.

It can be seen that increasing angular velocity increases rotational kinetic energy.

eimsori [14]3 years ago
4 0

Answer:

larger, because her angular speed is larger.

Explanation:

The rotational kinetic energy is proportional to the square of the angular velocity while it is linearly proportional to the moment of inertia. So the increase of angular speed will have a larger effect of the kinetic energy than the decrease of the moment of inertia.

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A sound wave with a waveenght of 2.5 meters traves 660 meters in 2 seconds calculate the frequemcy of the wave to cacuation the
finlep [7]

The frequency of the wave is 132 Hz

Explanation:

To calculate the speed of the wave, we can use the following formula:

v = \frac{d}{t}

where

d is the distance travelled by the wave

t is the time elapsed

For the sound wave in this problem, we have:

d = 660 m is the distance travelled

t = 2 s is the time interval considered

Substituting and solving for v, we find the speed of the sound wave:

v=\frac{660}{2}=330 m/s

Now we can calculate the frequency of the wave by using the wave equation:

v=f\lambda

where

v = 330 m/s is the speed of the wave

\lambda=2.5 m is the wavelength

f is the frequency

Solving for f, we find:

f=\frac{v}{\lambda}=\frac{330}{2.5}=132 Hz

Learn more about wavelength and frequency:

brainly.com/question/5354733

brainly.com/question/9077368

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7 0
3 years ago
NEED ANSWER ASAP what are the factors that affect the strength of a frictional force?
ololo11 [35]

    It's not the second one since color has nothing to do with force.   Also the third one isn't a factor since buoyant forces is the upward force of caused by fluid that opposes the object entering the liquid. The acceleration of the object and the mass of an object and how rough the surface are the only two factors in all the options.

8 0
4 years ago
Which circuit element is of special importance in AC circuits?
Norma-Jean [14]

Answer:

Explanation:capacitor

8 0
3 years ago
Read 2 more answers
A steel ball is released just below the surface of thick oil in a cylinder.
Viefleur [7K]

Answer:

Increasing

Explanation:

I Hope it Helps

6 0
3 years ago
A hunter stands on a frozen pond (frictionless) and fires a 4.20g bullet at 965m/s horizontally.The mass of hunter + gun is 72.5
Afina-wow [57]

Answer:

The the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.

Explanation:

Given;

mass of bullet, m₁ = 4.2 g = 0.0042 kg

mass of hunter + gun = 72.5 kg

velocity of the bullet, u = 965 m/s

Momentum of the bullet when it was fired;

P = mv

P = 0.0042 x 965

P = 4.053 kg.m/s

Determine the recoil velocity of the hunter.

Total momentum = sum of the individual momenta

Total momentum = momentum of the bullet + momentum of the hunter

Apply the principle of conservation of momentum, sum of the momentum is equal to zero.

P_{hunter} + P_{bullet} = 0\\\\P_{hunter}  = -P_{bullet}\\\\72.5v = -4.053\\\\v = \frac{-4.053}{72.5} \\\\v = - 0.056 \ m/s\\\\Thus, the \ recoil \ velocity \ of \ the \ hunter \ is \ 0.056 \ m/s, \ in \ opposite \ direction \ of \ the \ bullet.

Therefore, the the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.

6 0
4 years ago
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