The time it takes light from a flash camera to reach a subject 6.0 meters across a room in scientific notation is 2.0 *10^-8 s.
<u>Explanation:</u>
<u>Given</u>
t=?
d=6m
v=3*10^8 m/s
we have, v=d/t
here t=d/v
t=6m/3*10^8 m/s
v=2*10^-8 m/s
The time it takes light from a flash camera to reach a subject 6.0 meters across a room in scientific notation is 2.0 *10^-8 s.
<u></u>
Evaporation (or another word to use is water vapor.)
The range of the piece of paper is C) 1.4 m
Explanation:
The motion of the piece of paper is the motion of a projectile, which consists of two separate motions:
- A uniform motion along the horizontal direction, with constant velocity
- A uniformly accelerated motion along the vertical direction, with constant acceleration (the acceleration of gravity,
)
From the equation of motion, it is possible to find an expression for the range (the total horizontal distance covered) of a projectile, which is given by:

where
u is the initial velocity
is the angle of projection
g is the acceleration of gravity
For the piece of paper in this problem,
u = 4.3 m/s

Substituting,

Learn more about projectile motion:
brainly.com/question/8751410
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Answer:
B) The lightbulb uses 4,104,000 J more than the stereo.