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4 years ago

For precipitation to form, cloud droplets must grow in volume by roughly __________ times.

2 answers:

8 0

<span>For precipitation to form, cloud droplets must grow in volume by roughly one million times.

Hope I helped :)</span>

ziro4ka [17]4 years ago

7 0

The correct answer is by roughly one million times.

Any product of the condensation of atmospheric water vapor, which falls under gravity is known as precipitation. The main forms of precipitation are rain, drizzle, snow, sleet, and others.

All the precipitation give rise to clouds and the clouds are produced when water vapor in the atmosphere condenses and cools. With the condensation of water vapor, the formation of water droplets takes place, and if the formation of clouds takes place within or is moved into the part of the atmosphere, which is below freezing then the droplets turn into ice crystals.

In order to form precipitation, the cloud droplets must grow in volume by roughly one million times.

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Suppose that the weight (in pounds) of an airplane is a linear function of the amount of fuel (in gallons) in its tank. When car

Inessa [10]

Answer:

$W=2219pounds$

Explanation:

If the weight is a linear function of the amount of fuel, the following correlation is fulfilled :

$\frac{2153pounds-1999pounds}{46gallons-18gallons} = \frac{W-1999pounds}{58gallons-18galons}$

we solve the equation:

$W=2219pounds$

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3 years ago

A certain atom has atomic number Z = 25 and atomic mass number A = 52. a. What is the approximate radius of the nucleus of this

wlad13 [49]

Answer:

a)The approximate radius of the nucleus of this atom is 4.656 fermi.

b) The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

Explanation:

$r=r_o\times A^{\frac{1}{3}}$

$r_o=1.25 \times 10^{-15} m$ = Constant for all nuclei

r = Radius of the nucleus

A = Number of nucleons

a) Given atomic number of an element = 25

Atomic mass or nucleon number = 52

$r=1.25 \times 10^{-15} m\times (52)^{\frac{1}{3}}$

$r=4.6656\times 10^{-15} m=4.6656 fm$

The approximate radius of the nucleus of this atom is 4.656 fermi.

b) $F=k\times \frac{q_1q_2}{a^2}$

k= $9\times 10^9 N m^2/C^2$ = Coulombs constant

$q_1,q_2$ = charges kept at distance 'a' from each other

F = electrostatic force between charges

$q_1=+1.602\times 10^{-19} C$

$q_2=+1.602\times 10^{-19} C$

Force of repulsion between two protons on opposite sides of the diameter

$a=2\times r=2\times 4.6656\times 10^{-15} m=9.3312\times 10^{-15} m$

$F=9\times 10^9 N m^2/C^2\times \frac{(+1.602\times 10^{-19} C)\times (+1.602\times 10^{-19} C)}{(9.3312\times 10^{-15} m)^2}$

$F=2.6527 N$

The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

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3 years ago

Which of the following is not affect by muscles a blood temperature b digestion c hair growth d speech

Murrr4er [49]

Answer:

Explanation:

i would think c would be correct because

blood temperature IS affected by muscles

digestion IS affected by muscles

speech IS affected by muscles

so therefore <em>hair growth</em> IS NOT affected by muscles

<h2><u><em>Please mark Brainliest</em></u></h2>

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3 years ago

A monkey has a bit of a heavy for on the gas pedal. As soon as the light turns green the monkey pushes the gas pedal to the floo

Andrei [34K]

Answer:

$s=6.86m/s^2$

Explanation:

Hello,

In this case, considering that the acceleration is computed as follows:

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$a=\frac{28.82m/s-0m/s}{4.2s}\\ \\s=6.86m/s^2$

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3 years ago

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zhuklara [117]

Answer:

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Explanation:

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4 years ago