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Marrrta [24]
2 years ago
12

Jabar earns $5 for the first 10 pounds of newspaper he recycles, then $0.25 for each additional pound. Which expression represen

ts the amount he
earns for recycling p pounds of newspaper if p > 10?

A

5 +0.25 (p - 10)

B

(5 +0.25) P

с

5 + 0.25p

D

5 (10) +0.25p
Mathematics
1 answer:
slava [35]2 years ago
6 0
Am not sure but I think the answer is B
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2 years ago
Prove that $5^{3^n} + 1$ is divisible by $3^{n + 1}$ for all nonnegative integers $n.$
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When n=0, we have

5^{3^0} + 1 = 5^1 + 1 = 6

3^{0 + 1} = 3^1 = 3

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for n=k, that

3^{k + 1} \mid 5^{3^k} + 1

Now for n=k+1, we have

5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)

so we know the left side is at least divisible by 3^{k+1} by our assumption.

It remains to show that

3 \mid \left(5^{3^k}\right)^2 - 5^{3^k} + 1

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a^p \equiv a \pmod p

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5^3 \equiv 5 \pmod 3 \implies (5^3)^x \equiv 5^x \pmod 3

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5^{3^k} \equiv 5^{3\times3^{k-1}} \equiv \left(5^{3^{k-1}}\right)^3 \equiv 5^{3^{k-1}} \pmod 3

which goes all the way down to

5^{3^k} \equiv 5 \pmod 3

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\left(5^{3^k}\right)^2 - 5^{3^k} + 1 \equiv 5^2 - 5 + 1 \equiv 21 \equiv 0 \pmod3

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1 year ago
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