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Mila [183]
3 years ago
13

I’m confused on the type of angles these are and how to solve them . (Parallel lines and Transversals)

Mathematics
1 answer:
svp [43]3 years ago
4 0

Answer:

7) 49°

8) 77°

9) 87°

10) 135°

Step-by-step explanation:

7) The angles are between the parallel lines, so are "interior." They are on opposite sides of the transversal, so are "opposite interior" angles. Such angles are congruent, so ...

... ? ≅ 49°

8) The angles are adjacent interior angles, so are supplementary.

... ? + 103° = 180°

... ? = 77°

9) The angles are outside the parallel lines, so are "exterior." They are on opposite sides of the transversal, so are "opposite exterior" angles. Such angles are congruent.

... ? ≅ 87°

10) These are vertical angles, so are congruent. (The other parallel line is irrelevant and doesn't need to be there for this relationship to be true.)

... ? ≅ 135°

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Step-by-step explanation:

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4x + 6y = -4

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If we add the two numbers on the right side of the equation, we get -2, which does not equal 0, meaning there are no solutions to this system of equations.

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3 years ago
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3 0
3 years ago
6y + 4 – 3y = -5 + y + 17
Luda [366]

Answer:

Step-by-step explanation:

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Which values are possible rational roots of 4x3+9x2−x+10=0 according to the rational root theorem? Select each correct answer. ±
navik [9.2K]

ANSWER


The possible rational roots are:


\pm\frac{1}{2},\pm2,\pm \frac{5}{2}


EXPLANATION


According to the rational root theorem, the possible rational roots of the polynomial,



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are all the possible factors of the constant term divided by all the possible factors of the coefficient of the highest degree of the polynomial.



Therefore we examine the numerator and denominator of the options provided to see if they are factors of 10 and 4 respectively.



For

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The same thing applies to \pm2,\pm \frac{5}{2} also.


As for


\pm \frac{2}{5}, 2 is a factor of 10 but 5 is not a factor of 2, hence it is not a possible rational root.


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3 years ago
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Answer:

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