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lutik1710 [3]
2 years ago
12

What is the slope of a line parallel to the line whose equation is 3x-3y=-453x−3y=−45.

Mathematics
1 answer:
torisob [31]2 years ago
8 0

Answer:

75.5x is the slope

453x+(-6y)=-45

-6y/-6y= y

-45/-6= 7.5

-453/-6= 75.5

y=7.5+ 75.5x

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