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3 years ago

6

A certain copper wire has a resistance of 10.5 ω. at what fraction of the length l must the wire be cut so that the resistance o

f one piece is 9.0 times the resistance of the other?

1 answer:

Delvig [45]3 years ago

6 0

The answer for that questions will be 759. Stars itir

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The water portion of Earth; one of the traditional subdivisions of Earth’s physical environment

Harrizon [31]

hydrosphere

hope this helps :)

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3 years ago

Batteries supply DC, direct current, which does not change in direction over time, though eventually they get exhausted.

SashulF [63]

My Anonymuos friend, I could not agree more with your statement.
Truer words have rarely if ever been expressed.

6 0

3 years ago

MARKING BRAINLIEST AND I NEED WORK SHOWN ! i’m a junior in high school

Irina-Kira [14]

Answer:

(1) t = 4.29 s

(2) h = 58.98 m

(3) v = 20.04 m/s (downward)

(4) h = 0.94 m

(5) v = 18.78 m/s

Explanation:

Assumption:

during downward motion, acceleration due to gravity, g is positive. (+g)

during upward motion, acceleration due to gravity, g is negative. (-g)

(1)

initial velocity of the baseball, u = 42.0 m/s

final velocity of the ball, v = 0

time of flight is given by;

v = u -gt

gt = u

t = u / g

t = 42 /9.8

t = 4.29 s

(2)

Given;

initial velocity of the golf, u = 0

final velocity of the golf, v = 34 m/s

the height of the cliff is given by;

v² = u² + 2gh

v² = 0 + 2gh

h = v²/2g

h = (34)²/(2x9.8)

h = 58.98 m

(3)

Given;

initial velocity of the rocket, u = 27 m/s

time of motion, t = 4.8s

final velocity, v = ?

v = u + gt

v = 27 + (-9.8 x 4.8)

v = 27 - 47.04

v = -20.04 m/s (the negative sign indicates downward motion of the rocket after 4.8 s)

(4)

Given;

initial velocity of the lizard, u = 4.3 m/s

final velocity of the lizard at maximum height, v = 0

the height rose by the lizard is given by;

v² = u² + 2(-g)h

0 = u² - 2gh

2gh = u²

h = u² / 2g

h = (4.3)²/(2 x 9.8)

h = 0.94 m

(5)

Given;

initial velocity of the person on the bridge, u = 0

height of the bridge, h = 18 m

final velocity of the person is the velocity at impact, v = ?

v² = u² + 2gh

v² = 0 + 2gh

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 18)

v = 18.78 m/s

3 0

3 years ago

The position of a train at a time 2 seconds is 100m from a station. Suppose its velocities at the end of 2 seconds and at the en

Leni [432]

vf²=vi²+2ad

5²=0+2a.100

a=0.125 m/s²

20²=0+2 x 0.125 x d

400 = 0.25d

d = 1600 m

8 0

2 years ago

A muon is traveling at 0.995

LenaWriter [7]

The momentum of a relativistic particle is given by
$p= \gamma m_0 v$
where
$\gamma= \frac{1}{ \sqrt{1- \frac{v^2}{c^2} } }$ is the relativistic factor
$m_0$ is the rest mass of the particle
v is the speed particle

The rest mass of the muon is 207 times the rest mass of the electron:
$m_0 = 207 m_e = 207 \cdot 9.1 \cdot 10^{-31} kg=1.88 \cdot 10^{-28} kg$
The muon is moving at speed 0.995 c, therefore its velocity is
$v=0.995 c=0.995 \cdot 2.998 \cdot 10^8 m/s =2.983 \cdot 10^8 m/s$
And the relativistic factor is
$\gamma = \frac{1}{ \sqrt{1- (\frac{0.995 c}{c})^2 } } =10.01$

If we plug these numbers into the first equation, we find the muon momentum:
$p= \gamma m_0 v=(10.01)(1.88 \cdot 10^{-28} kg)(2.983 \cdot 10^8 m/s)=$
$=5.61 \cdot 10^{-19} kgm/s$

3 0

3 years ago