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Anastasy [175]
3 years ago
13

Helpppppppppppppppppppp

Mathematics
1 answer:
Effectus [21]3 years ago
7 0
Simple proportions.

You want a 1:5 ratio.
You have a 5:1 ratio.
So you add another 24 drops of white.
5:25 = 1:5 
or
5/x = 1/5 and cross multiply.
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GHJK is a square with diagonals intersecting at L. Given that GH=2 and GL=square root of , complete the statement
Dafna11 [192]

Answer:

GL = square root of 2 = √2

Step-by-step explanation:

Given: GHJK is a square and its diagonals intersect at L

GJ and HK are its two diagonals.

We know that in a square diagonals bisect each other and if length of side is a, then length of its diagonal = √2 a.

Therefore, GJ=HK = √2×2

Since, diagonal intersect at L , L is mid point of GJ and HK

Therefore, GL = √2×2/2 = √2

Hence, GL = square root of 2

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3 years ago
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1.7484450 is the answer
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Dovator [93]
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3 years ago
What is the magnitude of -3 +4i?
Goshia [24]

Answer:

we have

-3+4i

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|z|=\sqrt{( - 3) {}^{2}  + 4 {}^{2} }

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6 0
3 years ago
Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?
monitta

Answer:

(x-7)^2+(y-2)^2=34

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

(x-7)^2+(y-2)^2=r^2

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

(2-7)^2+(5-2)^2=r^2

Solve for <em>r: </em>

<em />(-5)^2+(3)^2=r^2<em />

Simplify. Thus:

25+9=r^2

Finally, add:

r^2=34

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

(x-7)^2+(y-2)^2=34

4 0
2 years ago
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