Answer:
GL = square root of 2 = √2
Step-by-step explanation:
Given: GHJK is a square and its diagonals intersect at L
GJ and HK are its two diagonals.
We know that in a square diagonals bisect each other and if length of side is a, then length of its diagonal = √2 a.
Therefore, GJ=HK = √2×2
Since, diagonal intersect at L , L is mid point of GJ and HK
Therefore, GL = √2×2/2 = √2
Hence, GL = square root of 2
Answer:

Step-by-step explanation:
We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).
First, recall that the equation of a circle is given by:

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.
Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

Solve for <em>r: </em>
<em />
<em />
Simplify. Thus:

Finally, add:

We don't need to take the square root of both sides, as we will have the square it again anyways.
Therefore, our equation is:
