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3 years ago

Question 2 Find three consecutive odd integers whose sum is 99.

Mathematics

2 answers:

algol [13]3 years ago

8 0

Answer:

31, 33, 35

Step-by-step explanation:

Let 2n+1 be the first odd number. What will the next one be? Add two:

Let 2n+3 be the next odd number. Again, what is the next one? Add two:

Let 2n+5 be the third odd number.

The sum of those three numbers must be 99. You don't have to have the parenthesis here, but I think they help clarify where everything comes from.

(2n+1) + (2n+3) + (2n+5) = 99

Add like terms, and solve for n:

6n + 9 = 99

6n = 90

n = 15

The three odd numbers we want are:

2(15)+1 = 31

2(15)+3 = 33

2(15)+5 = 35

Double check: 31+33+35 = 99?

wariber [46]3 years ago

8 0

Answer:15+84

35+64

79+20

Step-by-step explanation:

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balandron [24]

Answer:

$573

Step-by-step explanation:

955* 0.60=573

10% of 955= 95.5

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4 0

3 years ago

PLEASE HELP ME ASAP I REALLY NEED HELP!!!

padilas [110]

1) $\overline{UP}$

2) $\overline{UP} \cong \overline{UP}$

3) $\overline{UR}$

4) $\overline{PR}$

5) $\triangle OUP \cong \triangle RUP$ by SSS

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2 years ago

A village fete has a children’s running race each year, run in heats of up to ten children. For each heat the first three contes

bekas [8.4K]

Answer: 1) 1/3,654 2) 3/406 3) 72,684,900,288,000 4) 120

Step-by-step explanation:

1) First and Second and Third

$\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}\times \dfrac{1\ remaining\ prize}{27\ remaining\ people}=\dfrac{6}{21,924}\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad =\large\boxed{\dfrac{1}{3,654}}$

2) First and Second

$\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}=\dfrac{6}{812}=\large\boxed{\dfrac{13}{406}}$

$3)\quad \dfrac{29!}{(29-10)!}=\large\boxed{72,684,900,288,000}$

$4)\quad _{10}C_3=\dfrac{10!}{3!(10-3)!}=\large\boxed{120}$

8 0

3 years ago

Reduce to simplest form. -3/5 + (-8/2) =

Dominik [7]

Answer:

The answer is -4 3/5

Step-by-step explanation:

Let's reduce to its simplest form:

-3/5 + (-8/2) =

Step 1: Lowest Common Denominator (10):

- 6/10 + (-40/10) =

Step 2: Solve the parentheses:

- 6/10 - 40/10 =

Step 3: Subtract the fractions:

-46/10

Step 4: Simplify (Dividing by 2):

-23/5

Step 5: Converting the fraction to mixed number:

-4 3/5

The answer is -4 3/5

3 0

4 years ago

Why is ac smaller than ad if they both look very close

kakasveta [241]

Let's begin by listing out the information given to us:

We start out by observing that Triangles MKR & ACD are similar or proportional

$\begin{gathered} MK=21;AC=\text{?} \\ MR=24;AD=28\frac{4}{5} \\ KR=CD=\text{?} \end{gathered}$

We will solve for the missing side by using the similar triangle theorem. This is shown below:~

$\begin{gathered} \Delta MKR\approx\Delta ACD \\ \frac{MK}{AC}=\frac{MR}{AD} \\ \frac{21}{AC}=\frac{24}{28\frac{4}{5}} \\ \text{Cross multiply, we have:} \\ 24\cdot AC=28\frac{4}{5}\cdot21 \\ AC=\frac{28\frac{4}{5}\cdot21}{24}=25\frac{1}{5} \\ AC=25\frac{1}{5} \end{gathered}$

8 0

1 year ago