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3 years ago

Question 2 Find three consecutive odd integers whose sum is 99.

Mathematics

2 answers:

algol [13]3 years ago

8 0

Answer:

31, 33, 35

Step-by-step explanation:

Let 2n+1 be the first odd number. What will the next one be? Add two:

Let 2n+3 be the next odd number. Again, what is the next one? Add two:

Let 2n+5 be the third odd number.

The sum of those three numbers must be 99. You don't have to have the parenthesis here, but I think they help clarify where everything comes from.

(2n+1) + (2n+3) + (2n+5) = 99

Add like terms, and solve for n:

6n + 9 = 99

6n = 90

n = 15

The three odd numbers we want are:

2(15)+1 = 31

2(15)+3 = 33

2(15)+5 = 35

Double check: 31+33+35 = 99?

wariber [46]3 years ago

8 0

Answer:15+84

35+64

79+20

Step-by-step explanation:

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cluponka [151]

Answer:

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Step-by-step explanation:

Let U be the set of patients who reported at the hospital on that day

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Let I be the set of injured patients

Then the given data can be written as:

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Using the formula for the cardinal number of union of three sets:

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Read 2 more answers