Question

Question 2 Find three consecutive odd integers whose sum is 99.

Answer 1

Answer:

31, 33, 35

Step-by-step explanation:

 

Let 2n+1 be the first odd number. What will the next one be? Add two:

Let 2n+3 be the next odd number. Again, what is the next one? Add two:

Let 2n+5 be the third odd number.

 

The sum of those three numbers must be 99. You don't have to have the parenthesis here, but I think they help clarify where everything comes from.

 

(2n+1) + (2n+3) + (2n+5) = 99

 

Add like terms, and solve for n:

 

6n + 9 = 99

6n = 90

n = 15

 

The three odd numbers we want are:

2(15)+1 = 31

2(15)+3 = 33

2(15)+5 = 35

 

Double check: 31+33+35 = 99?

Answer 2

Answer:15+84

35+64

79+20

Step-by-step explanation: