Answer:
Sorry, I am not quite sure what the question is.
Answer:
6 matches
Step-by-step explanation:
Let’s call the teams A B C D
A will play B C D = 3 matches
B will play only C and D as it already played A, making 2 matches
C will play D, making 1 match
D has already played all
Total number of matches is thus 3 + 2 + 1 = 6 matches
There are C(5,2) = 10 ways to choose 2 contraband shipments from the 5. There are C(11, 1) = 11 ways to choose a non-contraband shipment from the 11 that are not contraband. Hence there are 10*11 = 110 ways to choose 3 shipments that have 2 contraband shipments among them.
There are C(16,3) = 560 ways to choose 3 shipments from 16. The probability that 2 of those 3 will contain contraband is
110/560 = 11/56 ≈ 19.6%
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C(n,k) = n!/(k!(n-k)!)
On average one out of 6 customers purchase fantasy books most frequently
