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TiliK225 [7]
2 years ago
13

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Mathematics
2 answers:
Citrus2011 [14]2 years ago
8 0

Answer:

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Step-by-step explanation:

erastovalidia [21]2 years ago
6 0
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What triangle can be obtuse?
True [87]

Answer:

Isosceles and scalene triangles can both be obtuse.

3 0
3 years ago
Can someone help me round these two numbers? I completely forgot how ‍
tigry1 [53]

Answer:

Step-by-step explanation:

If you are rounding to nearest tenth

2.6  1.9

Nearest hundredth

2.6   1.87

If the number to the right of the one you want to round is 5 or above, you go up a number. If it's below, you go down 1.

Hope this helps.

5 0
2 years ago
What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti
Marat540 [252]

Answer:

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

Step-by-step explanation:

Given

x^2 - 5x - 7 = 0

Required

Solve for x using:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

First, we need to identify a, b and c

The general form of a quadratic equation is:

ax^2 + bx + c = 0

So, by comparison with x^2 - 5x - 7 = 0

a = 1     b = -5      c = -7

Substitute these values of a, b and c in

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}

x = \frac{5 \± \sqrt{25 +28}}{2}

x = \frac{5 \± \sqrt{53}}{2}

Split the expression to two

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

To solve further in decimal form, we have

x = \frac{5 + 7.28}{2}  or  x = \frac{5 - 7.28}{2}

x = \frac{12.28}{2}  or  x = \frac{-2.28}{2}

x = 6.14 or x = -1.14

4 0
3 years ago
Literal Equations: 8c + 6j = 5p, for c
bixtya [17]
8c + 6j = 5p         Subtract 6j from both sides
       8c = 5p - 6j   Divide both sides by 8
         c = \frac{5p - 6j}{8}
3 0
3 years ago
Solve -(1+7x) - 6(-7 - x) = 36
Lelu [443]

Answer:

x = 5

Step-by-step explanation:

5 0
2 years ago
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