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2 years ago

HELPPP!!!

Mathematics

1 answer:

madam [21]2 years ago

4 0

Answer:

2 and a half @ 2.5 inches (sorry i can't type the fraction)

Step-by-step explanation:

english is my second language so sorry if you doesn't understand:

(1/2, 1/4)=(x,y)

based on the graph shown that each grid on the y axis represents 1/4, that is the smallest scale stood in the y axis.

this means 2 grid= 1/4 x 2 = 1/2 @ 0.5 inches.

since the '5 months-hair-length' is above about 2 grid above 2 inch:

2 inch + 0.5 inch= 2.5 inch

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Gemiola [76]

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1 year ago

What is the probability that it is not blue?

Alisiya [41]

1/3 chances the bubblegum is blue. To solve this problem you add all of the bubblegum together so 25+20+15 to get 60 then express it as a fraction to show only the blue pieces which would be 20/60 and you can simplify it to 1/3 or 33.33%

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2 years ago

Suppose the radius of a circle is 3 units what is the circumference

HACTEHA [7]

Answer:

$6\pi$ or approximately $18.85$ units

Step-by-step explanation:

The formula for finding the circumference of a circle is $C=2\pi r$ , where $C$ = circumference and $r$ = radius. In this case, $r=3$ , so after plugging that into $C=2\pi r$ , we get:

$C=2\pi r\\ = 2*\pi *3\\=6\pi$

Since $\pi$ is approximately $3.1415$ , $6\pi =6*3.1415=18.849$ , which rounds to $18.85$ . Therefore, the circumference of the circle is $6\pi$ , or approximately $18.85$ units. Hope this helps!

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2 years ago

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butalik [34]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

In a recent study of 42 eighth graders, the mean number of hours per week that they watched television was 19.6. Assume the popu

olya-2409 [2.1K]

Answer:

$19.6-2.42\frac{5.8}{\sqrt{42}}=17.43$

$19.6+2.42\frac{5.8}{\sqrt{42}}=21.77$

And the best option for this case would be:

a. (17.5, 21.7)

Step-by-step explanation:

Information given

$\bar X= 19.6$ represent the sample mean

$\mu$ population mean

$\sigma= 5.8$ represent the population deviation

n=42 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom, given by:

$df=n-1=42-1=41$

Since the Confidence is 0.98 or 98%, the significance would be $\alpha=0.02$ and $\alpha/2 =0.1$ , and the critical value would be $t_{\alpha/2}=2.42$

Replacing we got:

$19.6-2.42\frac{5.8}{\sqrt{42}}=17.43$

$19.6+2.42\frac{5.8}{\sqrt{42}}=21.77$

And the best option for this case would be:

a. (17.5, 21.7)

8 0

2 years ago