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nasty-shy [4]
3 years ago
10

The students in Ms. Gonzales' fifth grade math class earned the following grades on their first test: 46, 56, 64, 64, 72, 76, 77

, 82, 94, 96,99 What was the mean of the grades? (round to the nearest whole number) A. 826 OB. 75 O c. 76 OD. 64 O E 83​
Mathematics
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

75

Step-by-step explanation:

mean = average so add up all your numbers, then divide by the amount of numbers so

46 + 56 + 64 + 64 + 72 + 76 + 77 + 82 + 94 + 96 + 99 = 826

826 ÷ 11 = 75.09 (about)

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Rework problem 35 from the Chapter 2 review exercises in your text, involving auditioning for a play. For this problem, assume 9
sweet-ann [11.9K]

Answer: 1) 6300 ways

2) 2520 ways

3) 0.067

Step-by-step explanation:

For this problem, assume 9 males audition, one of them being Winston, 5 females audition, one of them being Julia, and 6 children audition. The casting director has 3 male roles available, 1 female role available, and 2 child roles available.

How many different ways can these roles be filled from these auditioners?

Available: 9M and  5F and 6C

Cast: 3M and 1F and  2C

As it is not ordered: C₉,₃ * C₅,₁ * C₆,₂

C₉,₃ = 9!/3!.6! = 84

C₅,₁ = 5!/1!.4! = 5

C₆,₂ = 6!/2!.4! = 15

C₉,₃ * C₅,₁ * C₆,₂ = 84.5.15 = 6300

How many different ways can these roles be filled if exactly one of Winston and Julia gets a part?

2 options Winston gets or Julia gets it:

1) Winston gets it but Julia no:

8 male for 2 spots

4 females for 1 spot

6 children for 2 spots

C₈,₂ * C₄,₁ * C₆,₂

C₈,₂ = = 8!/2!.6! = 28

C₄,₁ = 4!/1!.3! = 4

C₆,₂ = 6!/2!.4! = 15

C₈,₂ * C₄,₁ * C₆,₂ = 28.4.15 = 1680

2) Julia gets it but Winston does not

8 male for 3 spots

1 female for 1 spot

6 children for 2 spots

C₈,₃ * C₆,₂

C₈,₃ = 8!/3!.5! = 56

C₆,₂ = 6!/2!.4! = 15

C₉,₃ * C₆,₂ = 56.15 = 840

1) or 2) = 1) + 2) = 1680 + 840 = 2520

What is the probability (if the roles are filled at random) of both Winston and Julia getting a part?

8 male for 2 spots

1 female for 1 spot

6 children for 2 spots

C₈,₂ * C₆,₂

C₈,₂ = = 8!/2!.6! = 28

C₆,₂ = 6!/2!.4! = 15

C₈,₂ * C₆,₂ = 28.15 = 420

p = 420/6300 = 0.067

6 0
4 years ago
Help me please i don't know what to do
astra-53 [7]

Answer:

a. a = 1, b = -5, c = -14

b. a = 1, b = -6, c = 9

c. a = -1, b = -1, c = -3

d. a = 1, b = 0, c = -1

e. a = 1, b = 0, c = -3

Step-by-step explanation:

a. x-ints at 7 and -2

this means that our quadratic equation must factor to:

(x-7)(x+2) = 0

FOIL:

x^2 + 2x - 7x - 14 = 0

Simplify:

x^2 - 5x - 14 = 0

a = 1, b = -5, c = -14

b. one x-int at 3

this means that the equation will factor to:

(x-3)^2=0

FOIL:

x^2 - 3x - 3x +9 = 0

Simplify:

x^2 - 6x + 9 = 0

a = 1, b = -6, c = 9

c. no x-int and negative y must be less than 0

This means that our vertex must be below the x-axis and our parabola must point down

There are many equations for this, but one could be:

-x^2-x-3=0

a = -1, b = -1, c = -3

d. one positive x-int, one negative x-int

We can use any x-intercepts, so let's just use -1 and 1

The equation will factor to:

(x+1)(x-1)=0

This is a perfect square

FOIL:

x^2-1=0

a = 1, b = 0, c = -1

e. x-int at \sqrt{3} , -\sqrt{3}

our equation will factor to:

(x+\sqrt{3} )(x-\sqrt{3)} =0

This is also a perfect square

FOIL and you will get:

x^2 - 3 = 0

a = 1, b = 0, c = -3

4 0
2 years ago
I need help with this please!! ​
vovangra [49]

Answer:

{6x}^{3}  +  {9x}^{2}  - 18x + 3

Step-by-step explanation:

1. Expand by distributing sum groups.3x( {2x}^{2}  + 5x - 1) - 3( {2x}^{2}  + 5x - 1)

2. Expand by distributing terms.

{6x}^{3}  +  {15x}^{2}  - 3x - 3( {2x}^{2}  + 5x - 1)

3.Expand by distributing terms.

{6x}^{3}  +  {15x}^{2}  - 3x - ( {6x}^{2}  +  15x - 3)

4. Remove parentheses.

{6x}^{3}  +  {15x}^{2}  - 3x -  {6x}^{2}  - 15x + 3

5. Collect like terms.

{6x}^{3}  +  {15x}^{2}  -  {6x}^{2} ) + ( - 3x - 15x) + 3

6. Simplify.

{6x}^{3}  +  {9x}^{2}  - 18x + 3

Thus. the answer is,

{6x}^{3}  +  {9x}^{2}  - 18x + 3

5 0
3 years ago
Simplify: 19w5+ (-3075)
AleksAgata [21]
Simplified: 19w^5 - 3075
7 0
3 years ago
I need to know how to make the equations
Bogdan [553]
Asked and answered elsewhere.
brainly.com/question/9016540
3 0
3 years ago
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