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nasty-shy [4]
3 years ago
10

The students in Ms. Gonzales' fifth grade math class earned the following grades on their first test: 46, 56, 64, 64, 72, 76, 77

, 82, 94, 96,99 What was the mean of the grades? (round to the nearest whole number) A. 826 OB. 75 O c. 76 OD. 64 O E 83​
Mathematics
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

75

Step-by-step explanation:

mean = average so add up all your numbers, then divide by the amount of numbers so

46 + 56 + 64 + 64 + 72 + 76 + 77 + 82 + 94 + 96 + 99 = 826

826 ÷ 11 = 75.09 (about)

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If l and m are parallel lines, solve x and y (question 11)
Marta_Voda [28]

Answer:

\large \boxed{x= 18; y = 5}

Step-by-step explanation:

1. Calculate x

\begin{array}{rcll}7x - 23 & = & 3x + 49 & \text{Corresponding angles}\\7x & = & 3x + 72 & \text{Added 23 to each side}\\4x & = & 72 & \text{Subtracted 3x from each side}\\x & = & \mathbf{18} & \text{Divided each side by 4}\\\end{array}

2. Calculate y

\begin{array}{rcll}3x & = & 11y - 1 & \text{Corresponding angles}\\3 \times 18 & = & 11y - 1 & \text{Substituted the value of x}\\54 & = & 11y - 1 &\text{Simplified}\\55 & = & 11y & \text{Added 1 to each side}\\y & = & \mathbf{5} & \text{Divided each side by 11}\\\end{array}\\\large \boxed{\mathbf{x= 18; y = 5}}

 

Check:

7×18 - 23 = 3 × 18 + 49     3 × 18 = 11 × 5 - 1

126 - 23 = 54 + 49                54 = 55 - 1

       103 = 103                       54 = 54

OK.

7 0
4 years ago
Find the sum and product of the roots of the given equation 4x^2-3+6=0
Bingel [31]

Answer:

Step-by-step explanation:

4x^2-3x+6=0

You can't find this out by factoring, so you have to use the quadratic formula.

Quadratic Formula: (-b+/-√b^2-4ac)/2a

A = 4

B = -3

C = 6

Plug in!!

(-(-3)+/-√-3^2-4(4)(6))/2(4)

3+/-√9-96/8

3+/√-87/8

3+/- i√87/8

3/8+/- i√87/8

Answer:

Roots/Zeros:

3/8 + i√87/8

3/8 - i√87/8

Is that what you were looking for...?

5 0
3 years ago
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