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3 years ago

Will reward points!!! Someone please help me!!

Mathematics

2 answers:

Olenka [21]3 years ago

8 0

The question is just a black box. I would like to help you if you could attach a pic of the problem
You want solved

xeze [42]3 years ago

7 0

Help is on the way
five hours later
the box is still black
i’m losing faith in you
please..:: tell me what your question is

You might be interested in

Need help! Law of cosines...find b round to the nearest tenth please

dusya [7]

ANSWER

$B = 27.8 \degree$

EXPLANATION

The law of cosine is given by the formula:

${b}^{2} = {a}^{2} + {c}^{2} - 2bc \cos(B)$

From the diagram,

a=17, b=8, c=16

We substitute the given values into the formula to obtain:

${8}^{2} = {17}^{2} + {16}^{2} - 2(17)(16)\cos(B)$

$64 = 289+ 256- 544\cos(B)$

$64 = 545- 544\cos(B)$

$64 - 545 = - 544\cos(B)$

$- 481 = - 544\cos(B)$

$\frac{ - 481}{ - 544} = \cos(B)$

$cos(B) = 0.88419$

$B = \cos ^{ - 1} (0.88419)$

$B = 27.8 \degree$

3 0

4 years ago

Read 2 more answers

For a certain bathtub, it takes the hot water faucet

Valentin [98]

So, we know both faucets open, can do the whole job in 6minutes

ok, how much has the faster cold water faucet done in 1minute then?

well, let's say the the rate of speed of the cold water faucet is "c", so in 1minute it has done 1/c of the whole work

now, we know the hot water faucet is slower, it takes it 3 times as long, that means is 1/3 the speed of the cold water faucet, so, how much does the hot water faucet do in 1min? well, we know is 1/3 fast as the cold one, the cold one is 1/c, what's 1/3 of 1/c? well, 1/3 * 1/c

now, we know they both added together, can do the whole job in 6 minutes, so in 1minute, they've done 1/6 of the job then

thus

$\bf \begin{array}{cccccclllllll}
\cfrac{1}{c}&+&\left( \cfrac{1}{3}\cdot \cfrac{1}{c} \right)&=&\cfrac{1}{6}\\\\
\cfrac{1}{c}&+&\cfrac{1}{3c}&=&\cfrac{1}{6}\\\\
\uparrow &&\uparrow &&\uparrow \\
\textit{cold water rate}&&\textit{hot water rate}&&\textit{total done by both}
\end{array}\\\\
-----------------------------\\\\$

$\bf \cfrac{3+1}{3c}=\cfrac{1}{6}\implies 24=3c\implies \cfrac{24}{3}=c\implies \boxed{8=c}
\\\\\\
\textit{now, if the cold water faucet can do it in 8 minutes by itself}\\\\
\textit{then the hot water faucet can do it in 3 times as long}
\\\\\\
3\cdot 8\implies \boxed{24}$

4 0

3 years ago

Multiplication And Divisin Fact Families ,Will Mark Brainliest

viktelen [127]

Answer:

1) 56, 56, 56, -7

2) -1, -1, -1, -1

3) -7, 5, -35, -7

4) -4, -8, -4, -8

5) -21, -21, -21, -7

6) 10, -50, -5, -5

7) 48, 48, -4, 48

8) 6, -2, -2, -2

Step-by-step explanation:

Do I really have to explain? lol

Hope this helps.

8 0

3 years ago

Solve the equation. 3 4 (2a − 6) + 1 2 = 2 5 (3a + 20) a =

zvonat [6]

Answer:

a = 40 if simplified :)

7 0

3 years ago

Read 2 more answers

3. A ball was thrown into the air with an initial velocity of 72 feet per second. The height of the

timurjin [86]

Answer:

A. The maximum heigh is 81 feet

B. The ball will reach the maximum heiight at 2.25 seconds

C. The domain of the function is $t\in [0,4.5]$

D. The range of the function is $h(t)\in [0,81]$

E. 4.5 seconds

Step-by-step explanation:

A ball was thrown into the air with an initial velocity of 72 feet per second. The height of the ball after t seconds is represented by the equation:

$h= -16t^2 + 72t$

The maximum height will be at parabola's vertex. Find it:

$t_v=\dfrac{-b}{2a}\\ \\t_v=-\dfrac{72}{2\cdot (-16)}=\dfrac{72}{32}=\dfrac{9}{4}=2.25\\ \\h(t_v)=-16\cdot t_v^2+72\cdot t_v\\ \\h(2.25)=-16\cdot 2.25^2+72\cdot 2.25=81$

A. The maximum heigh is 81 feet

B. The ball will reach the maximum heiight at 2.25 seconds

C. Find where the parabola intersects the x-axis:

$h=0\Rightarrow -16t^2+72t=0\\ \\t(-16t+72)=0\\ \\t_1=0\ \text{or}\ 16t=72,\ t_2=\dfrac{9}{2}=4.5$

So, the domain of the function is $t\in [0,4.5]$

D. The range of the function is

$h(t)\in [0,81]$

E. The ball is at the air for 4.5 seconds

4 0

4 years ago