Step-by-step explanation:
For the quadratic equation to have 1 repeated real solution, the discriminant b² - 4ac must be zero.
=> (-z)² - 4(z - 5)(5) = 0
=> z² - 20(z - 5) = 0
=> z² - 20z + 100 = 0
=> (z - 10)² = 0
Therefore z = 10.
This is all percentages so...
4/9 = 44%
2/7 = 29%
1/10 = 10%
Total = 83%
So 17% of 630 is left over which = 107
5(n + 27) >= 6(n + 26)
5n + 135 >= 6n + 156
-n >= 21
n <= -21
Answer:
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Step-by-step explanation:
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