The smallest is 6
Three consecutive integers
X. Smallest 6
X+1. 7
X+2. Largest 8
X(X+1)= 4(X+2)+10
X^2+X= 4x+8+10
X^2+X-4x-18=0
X^2-3x-18=0
( X+3)(X-6)
X=-3. X=6
Don't use the negative
Check 6(7)= 4(8)+10
42=42
Answer:
2 or -2
Step-by-step explanation:
If x² - 8x = -12
Step 1
We find x by solving
x² - 8x = -12
We equate to zero
x² - 8x + 12 = 0
We factorise
x² - 6x - 2x + 12 = 0
x(x - 6) -2(x - 6) = 0
(x - 6) (x - 2) = 0
x - 6 = 0, x = 6
x - 2 = 0, x = 2
x = 6 or 2
Step 2
What is x - 4?
When x = 6
= 6 - 4 = 2
When x = 2
= 2 - 4 = -2
Therefore, x - 4 = 2 or -2
Answer:
6x^2-28x+30
Step-by-step explanation:
Answer:
There are infinite fractions greater then -7/12. An example is 7/8.
Step-by-step explanation:
b=a-80
c=b-61
c=a-141
a+b+c=3a-221=430
3a=651
a=217 & b =137 & c=76
