Second time...40 pts! Find the surface area of the model below (image included).

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

7 0

4 years ago

Please answer the problem below

8_murik_8 [283]

Answer:

d) m<ADC=44°

Step-by-step explanation:

7x-19=9x-37

-19+37=9x-7

18=2x

x=9

m<ADC=9x-37=9(9)-37=81-37=44

8 0

3 years ago

Read 2 more answers

Missy is 1.5 meters tall and cast a 9-meter shadow. How long is the shadow of a 6-meter flagpole beside.

PIT_PIT [208]

Answer:

36 meters

Step-by-step explanation:

9 divided by 3 is 3

That means for every 1 meters is 6 meters shadow wise because 3 meters equal to .5 meters.

6 meters of the pole times 6 meters per one real meter equals 36 shadow meters.

Hope that helped, if it did please give me the brainliest.

6 0

3 years ago

Read 2 more answers

23 points please help simplify the square root sqrt (32x^2) if x>=0

dexar [7]

Answer:

4√2x.

Step-by-step explanation:

√32 = √2*√16 = 4√2.

√x^2 = x.

3 0

2 years ago

Armando and Bianca are 290 feet apart when they start walking toward one another. Bianca walks twice as fast as

aivan3 [116]

9514 1404 393

Answer:

d = 290 -3x

Step-by-step explanation:

For each x feet that Armondo travels toward Bianca, Bianca travels 2x feet toward Armondo. The net effect is that the distance between them decreases by x+2x = 3x feet. The distance starts at 290 feet when x=0, so the distance can be described by ...

d = 290 -3x

3 0

3 years ago