Answer:
Yes. Burning usually observes this kind of law.
Explanation:
- The law of conversion of mass states that mass can never be formed nor can it be eradicated.
- This means that in case of burning, the amount of matter before and after will remain to be the same.
- It doesn't change at all.
- In conclusion, there's no form of change that can be able to affect matter.
Answer:
Structure 1 formal charges:
N₁ = +1; O₁₁ = +1; O₁₂ = -1; N₂ = 0; N₃ = +1; O₃₁ = -1; O₃₂ = -1
Structure 2 formal charges:
N₁ = +1; O₁₁ = +1; O₁₂ = -1; N₂ = -1; N₃ = +1; O₃₁ = -1; O₃₂ = +1
Structure 3 formal charges:
N₁ = +1; O₁₁ = -1; O₁₂ = -1; N₂ = +1; N₃ = +1; 0₃₁ = -1; O₃₂ = -1
Explanation:
The formal charge of an atom in a molecule is the charge assigned to the atom if the electrons in all chemical bonds were redistributed evenly between the atoms.
Formal charge can be calculated as follows:
Formal charge = number of valence shell electrons in the neutral atom − ( number of lone pair electrons + ½ bonding electrons)
Structure 1:
N₁ = 5 - 4 = +1
O₁₁ = 6 - 5 = +1
O₁₂ = 6 - 7 = -1
N₂ = 5 - 5= 0
N₃ = 5 - 4 = +1
O₃₁ = 6 - 7 = -1
O₃₂ = 6 - 7 = -1
Structure 2:
N₁ = 5 - 4 = +1
O₁₁ = 6 - 5 = +1
O₁₂ = 6 - 7 = -1
N₂ = 5 - 6= -1
N₃ = 5 - 4 = +1
O₃₁ = 6 - 7 = -1
O₃₂ = 6 - 5 = +1
Structure 3:
N₁ = 5 - 4 = +1
O₁₁ = 6 - 7 = -1
O₁₂ = 6 - 7 = -1
N₂ = 5 - 4 = +1
N₃ = 5 - 4 = +1
0₃₁ = 6 - 7 = -1
O₃₂ = 6 - 7 = -1
Answer:
0.000239 M
Explanation:
Na2S(aq) + CuSO4(aq) → Na2SO4(aq) + CuS(s)
molar mass of = 159.609 g/mol
molar mass of CuS = 95.611 g/mol
if 159.609 g/mol yielded 95.611 g/mol of CuS
then x g of CuSO4 that yielded 0.0183 g = 159.609 × 0.0183 / 95.611 = 0.0305 g
molar concentration = mole / volume in liters
number of mole of CuSO4 in the water sample = 0.0305 g / 159.609 g/mol = 0.000191 moles
molar concentration of CuSO4 = 0.000191 moles / 0.8 L = 0.000239 M
since when 1 mole of CuSO4 will dissociate to produce 1 mole of Cu2+
the molar concentration Cu2+ = 0.000239 M
I believe the answer is an ion.