100 times less H+
A solution at ph 10 contains<u> </u><u>100 times less H+</u> than the same amount of solution at ph 8.
<h3>The pH scale: How does it function?</h3>
- The pH scale determines how acidic or basic water is.
- The range is 0 to 14, with 7 representing neutrality.
- Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7.
- In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.
<h3>How does the pH change when two acids are combined?</h3>
- An acid's strength increases with the quantity of hydrogen ions it releases.
- The pH of the strong acids is between 1 and 2.
- We may observe that there is no response when two acids of the same strength are combined.
- It's because the end product will be neutral and the pH won't change.
<h3>How is pH value determined?</h3>
There are two ways to measure pH:
- colorimetrically with indicator fluids or sheets
- electrochemically with electrodes and a millivoltmeter for greater accuracy (pH meter).
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A magnet because it will remove only metal and not the saw dust
Hope this helps
Answer:0.8742j/g°C
Explanation: SOLUTION
GIVEN
length of bar=1.25m
mass 382g
temperature= 20°C to 288°C
Q=89300J
Specific Heat Capacity will be calculated using
Q=mC∆T
where
C = specific heat capacity
Q = heat
m = mass
Δ T = change in temperature
C=Q/ m∆T
=89300/382X(288-20.6)
=0.8742j/g°C
Answer:
ΔH for formation of 197g Fe⁰ = 1.503 x 10³ Kj => Answer choice 'B'
Explanation:
Given Fe₂O₃(s) + 2Al⁰(s) => Al₂O₃(s) + 2Fe⁰(s) + 852Kj
197g Fe⁰ = (197g/55.85g/mol) = 3.527 mol Fe⁰(s)
From balanced standard equation 2 moles Fe⁰(s) => 852Kj, then ...
3.527 mole yield (a higher mole value) => (3.527/2) x 852Kj = 1,503Kj (a higher enthalpy value).
______
NOTE => If 2 moles Fe gives 852Kj (exo) as specified in equation, then a <u>higher energy value</u> would result if the moles of Fe⁰(s) is <u>higher than 2 moles</u>. The ratio of 3.638/2 will increase the listed equation heat value to a larger number because 197g Fe⁰(s) contains more than 2 moles of Fe⁰(s) => 3.527 mole Fe(s) in 197g. Had the problem asked for the heat loss from <u>less than two moles Fe⁰(s)</u> - say 100g Fe⁰(s) (=1.79mole Fe⁰(s)) - then one would use the fractional ratio (1.79/2) to reduce the enthalpy value less than 852Kj.
, carboxyl group exists as
(charged)
(neutral)
(charged)
