Atomic mass of Sulfur = 32g
32g of Sulfur is one mole.
1g of Sulfur is 
96.21g of Sulfur is 
I believe it is "empirical formula"
Answer:
2.03
Explanation:
Let's <u>assume we have 1 L of the solution</u>:
- There would be 2.07 ethylene glycol moles.
- The solution would weigh (1000 mL * 1.02 g/mL) = 1020 g.
With that information we can <u>calculate the molality</u>:
- molality = moles of solute / kg of solvent
- molality = 2.07 moles / (1020 ÷ 1000) = 2.03 m
Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.
C protons, elctrons 093939393
Is there any choices or is this a fill in the blank question?
