The answers to each of the given problems are;
1) Sum of two smallest integers = 23
2) 3x + 6
3) 7.5 m/s²
<h3>How to find the sum of consecutive Integers?</h3>
1) We are told that sum of 4 consecutive integers is increased by 20 and equals 70. Thus, we have;
x + (x + 1) + (x + 2) + (x + 3) + 20 = 70
4x + 26 = 70
4x = 70 - 26
4x = 44
x = 44/4
x = 11
Thus, sum of two smallest integers = 11 + 11 + 1 = 23
2) Let the consecutive odd numbers be;
x, (x + 2) and (x + 4)
Sum of these consecutive odd numbers is;
x + x + 2 + x + 4 = 3x + 6
3) We are given the equation to find the acceleration as;
(v_final)² - (v_initial)² = 2ad
We are given;
v_final = 40 m/s
v_initial = 10 m/s
d = 100 m
Thus;
40² - 10² = 2a(100)
1500 = 200a
a = 1500/200
a = 7.5 m/s²
Read more about sum of integers at; brainly.com/question/17695139
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Answer:
your answer will be <em><u>C. y = x-4</u></em>
Step-by-step explanation:
hope it helps you...
7.5*.2=1.5
- 1.5= 6.5 w/ 20% off
6.5*0.0525=0.34125- rounded= .34+6.5=
$6.84
Hope this helps!!!!
A negative times a negative is a positive. I am not sure if that's the question, but hopefully that helps if it was.
Answer:
1/2
Step-by-step explanation:
We first find the least common multiple, which is 6. Therefore, we can multiply 1/3 x 2/2 (since 2/2 is equal to one and won't change the final amount) and get 2/6. 2/6+1/6=3/6, or 1/2.
