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3 years ago

Sven is thinking of two numbers.thesum is 12 the difference is 4 what are the two numbers

Mathematics

2 answers:

vladimir2022 [97]3 years ago

5 0

The answer is 4 and 8.

8 + 4 = 12

8 - 4 = 4

kvasek [131]3 years ago

4 0

I tried each possible combination and quickly found the answer, that's how it looks:

11 + 1 = 12
11 - 1 = 10

10 + 2 = 12
10 - 2 = 8

9 + 3 = 12
9 - 3 = 6

<u>8 + 4 = 12</u>
<u>8 - 4 = 4</u>

(...)

So the numbers Sven was thinking of are 8 and 4.

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How do you write 100 s a fraction, mixed number, or whole number

disa [49]

In fraction 100/100
In mixed number 10 0/10
Simplest form = 100

I hop this helps! :)

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2 years ago

It takes 12 men 8 days to construct a wooden shed. How many days will 15 men take?

Fynjy0 [20]

Answer:

10 days.

Step-by-step explanation:

8÷12 (because you can not divide people.

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take that and multiply it by 15

you will get 10

6 0

3 years ago

Please Help!!! NOW!!! Need answer, and quick.

cluponka [151]

40 or 45 degrees I say dis cuz if u find da overall area then u can find the degrees

5 0

3 years ago

Read 2 more answers

Mathematics

Vladimir [108]

Answer:

there no data

Step-by-step explanation:

Find the median of the first and third quartiles81, 69 ,90, 79, 59, 125, 95, 116, 183, 97, 92, 50, 122, 55, 9250, 55, 59, 69, 79, 81, 90, 92, 92, 95, 97, 116, 122, 125, 183.The first quartile: 50, 55, 59, 69, 79, 81, 90: median of the first quartile is 69The third quartile: 92, 95, 97, 116, 122, 125, 183: median of the third quartile is 116.The interquartile range is the difference between the median of both the first and third quartile: which is 116 - 69 = 47.There are no outliers in this set of data

4 0

2 years ago

A mouse climbs up a well of 86 meters. It advances 14 meters during the night, but during the day it retreats 2. The mouse will

Deffense [45]

Step-by-step explanation:

we assume day and night are equally long.

and the mouse will start at night of day 1.

then, on day 2, it will first retreat 2 meters (during daylight) and then advance 14 meters (at night).

so, on every full day, the mouse will effectively advance 12 meters (-2 + 14 = 12).

with a starting value of 14 (the first night).

so, we are getting an arithmetic sequence

an = an-1 + c

c = 12 in our case.

a1 = 14

a2 = a1 + 12 = 14+12 = 26

a3 = a2 + 12 = a1 + 12 + 12 = 14 + 2×12 = 38

an = a1 + (n-1)×12 = 14 + 12(n-1)

at what n will it reach 86 ?

86 = 14 + 12(n-1) = 14 + 12n - 12 = 2 + 12n

84 = 12n

n = 7

so, on the 7th day the mouse will reach the surface (if we truly count the first starting night day 1 - this is up to your teacher, but I would).

7 0

2 years ago