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elena-s [515]
3 years ago
12

A collection of books is set up into 34 rows. The first row has 96 books, and each row after that one

Mathematics
2 answers:
Tresset [83]3 years ago
8 0

Answer:

Part A: 3197

Part B: 62

Step-by-step explanation:

Part A: To make this easier just multiply 96 books by 34 rows which is 3264 books, but then since you are taking away 2 books for every row, multiply 2 by the 34 rows which is 68 but since the first row starts at 96 we will take away 1 row from the 68 which is 67. Then subtract 67 from the 3264 books and get 3197 books.

Part B: To make this easier just multiply 17 by 2 since we know for every row, 2 books are taken away and that equals 34 so subtract 34 from 96 and get 62.

Vladimir79 [104]3 years ago
4 0

Answer:

a(17) = 64

Step-by-step explanation:

you can create an arithmetic sequence formula as follows:

a(n) = a(1) + d(n-1)   where a(1) is the first value and d is the common difference

a(17) = 96 -2(17-1)

a(17) = 96 - 32

a(17) = 64

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1. 0.7421 = 74.21% probability the elevator is overloaded.

2. D.​No, there is a good chance that 10 randomly selected people will exceed the elevator capacity.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that weights of males are normally distributed with a mean of 166 lb and a standard deviation of 29 lb​.

This means that \mu = 166, \sigma = 29

Sample of 10.

This means that n = 10, s = \frac{29}{\sqrt{10}}

1.The probability the elevator is overloaded is?

Probability that the sample mean is above 160 pounds, which is 1 subtracted by the p-value of Z when X = 160. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 166}{\frac{29}{\sqrt{10}}}

Z = -0.65

Z = -0.65 has a p-value of 0.2579.

1 - 0.2579 = 0.7421

0.7421 = 74.21% probability the elevator is overloaded.

2. Does this elevator appear to be​ safe?

High probability of the elevator being overloaded, so not safe. Correct answer is given by option D.

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3 years ago
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