Answer:
False
Step-by-step explanation:
(3)(5)>15
15>15
False
The question is:
Check whether the function:
y = [cos(2x)]/x
is a solution of
xy' + y = -2sin(2x)
with the initial condition y(π/4) = 0
Answer:
To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.
Let us do that.
y = [cos(2x)]/x
y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]
Now,
xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x
= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)
= -2sin(2x)
Which is the right hand side of the differential equation.
Hence, y is a solution to the differential equation.
Amu of unknown element = 40 - (20% * 40)
= 40 - 8
= 38 amu
therefore, the approximate weight of the unknown element is 38 amu.
hope this helps.
Answer:
Step-by-step explanation:
Use similar triangles and proportions to solve:
and cross multiply:
4(6 + x) = 60 and
24 + 4x = 60 and
4x = 36 so
x = 9
