Ask question

Ask question

All categories

3 years ago

15

A company is expanding its building area from 13,500 square feet to 16,470 square feet. What is the percentage increase of the a

rea of the building space?

1 answer:

Solnce55 [7]3 years ago

3 0

Answer:

.22 or 22% increase

Step-by-step explanation:

16470-13500=2970 this is the amount it is increasing

2970/13500=.22 the percent increase

You might be interested in

What is -6(-3+5r)=-5-7r

inna [77]

Answer:

r = 1

Step-by-step explanation:

Use the distributive property to multiply −6 by −3+5r.

18−30r=−5−7r

Add 7r to both sides.

18−30r+7r=−5

Add −30r and 7r to get −23r.

18−23r=−5

Subtract 18 from both sides.

−23r=−5−18

Subtract 18 from −5 to get −23.

−23r=−23

Divide both sides by −23.

r=−23/−23

Divide −23 by −23 to get 1.

r=1

8 0

3 years ago

Ted is constructing an equilateral triangle. He draws a segment with his straightedge and labels the endpoints A and B. He then

gladu [14]

Answer:

Step-by-step explanation:

Keep the same compass opening, place the compass point on B, and draw a circle.

3 0

3 years ago

Ray is reading a book of 150 pages at a constant rate of 25 pages per hour. Let’s consider the following function: the pages lef

sineoko [7]

Question:

R U CONSTIPATED?

4 0

3 years ago

Abc congruent to pqr which of the following congruence statement is correct

rusak2 [61]

Answer:

I know the answer

Step-by-step explanation:

5 0

3 years ago

Suppose a certain study reported that 27.7% of high school students smoke.

Norma-Jean [14]

<u>Given</u>:

Probability of student smoke,

P = 27.7%

= 0.277

Number of students,

n = 632

$q = 1-p$

$=1-0.277$

$=0.723$

(i)

Here,

Number of students (n) = 60

then,

⇒ $n_P=60\times 0.277$

$=16.62$

⇒ $n_q=60\times 0.723$

$=43.38$

We can see that $n_P > 10$ and $n_q>10$ so the normal approximation condition are met.

Now,

$\mu = n_P= 16.62$

$\sigma = \sqrt{n_{Pq}}$

$= \sqrt{60\times 0.277\times 0.723}$

$=3.9664$

Now,

⇒ $P(X$

$=P(Z_{18.5})$

The Z-score is:

= $\frac{18.5-16.62}{3.4664}$

= $0.5423$

hence,

The probability will be:

⇒ $P(Z_{18.5}) = 0.7062$

or,

⇒ $P(Z$

(ii)

Here,

Number of students (n) = 75

$\mu = n_P = 75\times 0.277$

$=20.775$

$\sigma = \sqrt{n_{Pq}}$

$=\sqrt{75\times 0.277\times 0.723}$

$=3.8756$

Now,

⇒ $P(X>17) = P(X> 17.5)$

$=1-P(X \leq 17.5)$

$=1-P(Z_{17.5})$

The Z-score is:

= $\frac{17.5-20.775}{3.8756}$

= $-0.9740$

then, $P(Z_{17.5}) = 0.165$

hence,

The probability will be:

⇒ $P(X>17) = 1-0.165$

$=0.835$

Learn more about probability here:

brainly.com/question/9825651

4 0

3 years ago