Answer: The first one
Step-by-step explanation:
equation of the line which has the given slope "m" and whivh passes through the given point...
a.(2,10) and m= -4
b.(4,-4) and m=3/2
c.(0,0) and m=3/5
Answer:
53°
Step-by-step explanation:
It is given that the total measurement of the two angles combined would equate to 116°.
It is also given that m∠WXY is 10° more then m∠ZXY.
Set the system of equation:
m∠1 + m∠2 = 116°
m∠1 = m∠2 + 10°
First, plug in "m∠2 + 10" for m∠1 in the first equation:
m∠1 + m∠2 = 116°
(m∠2 + 10) + m∠2 = 116°
Simplify. Combine like terms:
2(m∠2) + 10 = 116
Next, isolate the <em>variable</em>, m∠2. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, subtract 10 from both sides of the equation:
2(m∠2) + 10 (-10) = 116 (-10)
2(m∠2) = 116 - 10
2(m∠2) = 106
Next, divide 2 from both sides of the equation:
(2(m∠2))/2 = (106)/2
m∠2 = 106/2 = 53°
53° is your answer.
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I’m pretty sure the answer is D
Answer:
Step-by-step explanation:
Let the equation of the cosine function is,
y = Acos(Bx)
From the graph attached,
A = Amplitude = 
= 1
B = 
B = 
B = 
B = 4
Therefore, equation of the cosine wave given in the graph will be,
y = 1.Cos(4x)
y = Cos(4x)
