Question

A cylinderical container of height 28cm and diameter 18cm is filled with water. The water is then poured into another container with a rectangular base 27cm and width 11cm. Calculate the depth of the water in the container ( take π=22/7)

Answer 1

Answer:

h = 24 cm

Step-by-step explanation:

volume of water in the cylinder = volume of water in the rectangular base container

But ,

volume of cylinder = $\pi$$r^{2}$h

where:  is the radius and h is the height.

volume of cuboid = length x width x height

                             = l x w x h

So that;

$\pi$$r^{2}$h = l x w x h

But, r = $\frac{diameter}{2}$ = $\frac{18}{2}$ = 9 cm, height of cylinder = 28 cm, length = 27 cm, width = 11 cm, $\pi$ = $\frac{22}{7}$.

Thus,

$\frac{22}{7}$ x $(9)^{2}$ x 28 = 27 x 11 x h

$\frac{22}{7}$ x 81 x 28 = 27 x 11 x h

7128 = 297h

h = $\frac{7128}{297}$

  = 24

h = 24 cm

The depth of the water in the container is 24 cm.