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Y_Kistochka [10]
3 years ago
5

(100 points) Give a step by step explanation on how you solved this problem

Mathematics
2 answers:
puteri [66]3 years ago
5 0

Answer:

Step-by-step explanation:

Well you have to solve for X to find Y simplified.

Since both equations equal Y you can plug them together

3x+3=x-1

-x          -x

2x+3=-1

-3         -3

2x=-4

Divide -4 by 2 and you get X = -2 then plug X into both equations and boom

y= -3

Lina20 [59]3 years ago
4 0
Use substitution
Given both y values, you know that they have to be equal

3x + 3 = x - 1
2x + 3 = -1
2x = -4, divide by 2
x = -2
Now plug x value into any of the equation to find y value
y = 3(-2) + 3
y = -6 + 3, y = -3

Solution: x = -2, y = -3
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<h2>Numerical expressions are numbers and signs, like below.  The following are some examples of numerical expressions, numerical expressions do not use letters. 4 + 20 – 7, (2 + 3) – 7, (6 × 2) ÷ 20, 5 ÷ (20 × 3)   An algebraic expression uses letters and it says you to find "x/y/z". Example; 4+20xy-7x, (2x+3) - 7y+20.</h2>
7 0
3 years ago
$300 at 6% for 3 years
Charra [1.4K]
Its I=prt 
so plug it in
I=300(.06)3 i got .06 because you have 6% you have to move the decimal  the left twice 0.06 is what you get
now its basic multiplying
300 times .06 times 3
so it would be 54
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7 0
3 years ago
A city hosted a music festival that included three concerts. According to the sales database, 28% of the audience attended the f
Vitek1552 [10]

Answer:

P(X\cap Y\cap Z)=0.05

Step-by-step explanation:

From the question we are told that:

Percentage of audience in first concert P(X)=0.28

Percentage of audience in second concert P(Y)=0.42

Percentage of audience in third concert P(Z)=0.30

Audience Percentage at at-least one concert P(X \cup Y \cup Z)=0.80

Percentage of audience at first & second concert P(X \cap Y)=0.10

Percentage of audience in first & third concert P(X \cap Z)=0.08

Percentage of audience in second & third concert P(Y\cap Z)=0.07

 

Generally the equation for probability of attending all concerts P(X\cap Y\cap Z)is mathematically given by

P(X \cup Y \cup Z)=P(X)+P(Y)+P(Z)-P(X \cap Y)-P(X \cap Z)-P(Y\cap Z)+P(X\cap Y\cap Z)

P(X\cap Y\cap Z)=P(X \cup Y \cup Z)-P(X)-P(Y)-P(Z)+P(X \cap Y)+P(X \cap Z)+P(Y\cap Z)

P(X\cap Y\cap Z)=0.80-0.28-0.42-0.30+0.10+0.80+0.70

P(X\cap Y\cap Z)=0.05

Therefore the probability that a randomly selected audient attended all the concerts

P(X\cap Y\cap Z)=0.05

8 0
3 years ago
A test of 10 different types of candy are being tested. If a person is given 6 of the candies to taste how many combinations are
ASHA 777 [7]

There are 210 different possible combinations

<h3>How to determine the number of possible combinations?</h3>

The given parameters are:

  • Types of candy, n = 10
  • Candies to taste, r = 6

The number of possible combinations is calculated using:

Combination = nCr

This gives

Combination = 10C6

Apply the combination formula

Combination = (10!)/((10 - 6)!6!)

Evaluate

Combination = 210

Hence, there are 210 different possible combinations

Read more about combination at:

brainly.com/question/11732255

6 0
2 years ago
Read 2 more answers
What is the least amount of wrapping paper needed to wrap a gift box that measures 8 inches by 8 inches by 10 inches. Explain
frozen [14]

448 square inches.

The surface area of the box is 448 square inches so that is the least amount of paper needed to cover the box.

4 0
3 years ago
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