Answer:
Let the vectors be
a = [0, 1, 2] and
b = [1, -2, 3]
( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.
Let the cross product be another vector c.
To find the cross product (c) of a and b, we have
![\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%261%262%5C%5C1%26-2%263%5Cend%7Barray%7D%5Cright%5D)
c = i(3 + 4) - j(0 - 2) + k(0 - 1)
c = 7i + 2j - k
c = [7, 2, -1]
( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:
c / | c |
Where | c | = √ (7)² + (2)² + (-1)² = 3√6
Therefore, the unit vector is
![\frac{[7,2,-1]}{3\sqrt{6} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5B7%2C2%2C-1%5D%7D%7B3%5Csqrt%7B6%7D%20%7D)
or
[ 
, 
, 
]
The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:
[ 
, 
, 
]
In conclusion, the two unit vectors are;
[ , , ]
and
[ , , ]
<em>Hope this helps!</em>
Answer:
4
Step-by-step explanation:
he should have gotten 45 back
but he only got 33
so the DIFFERENCE is how much he got in batteries, how many packs? well 45−33 = 12 12÷3=4
Answer: 315 miles
Step-by-step explanation:
let onward speed = x mph, then distance = 7x
return speed = (x+18) mph, (same) distance = 5(x+18)
equating the two,
7x = 5(x+18)
2x = 90 ==> x = 45 mph
so distance = 7*45 = 315 miles
The equation can be split into two equations:
y = log 6x
y = log 2(x + 4)
which is the system of equations that Omar can use to graph the single equation. The equations are logarithmic equations. They can be plotted directly into the coordinate system, use a logarithmic scale coordinate system, or linearize the equations before plotting.
Answer:
120
Step-by-step explanation:
