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liraira [26]
2 years ago
15

What did you learn, observe and discover in this pr

Mathematics
1 answer:
expeople1 [14]2 years ago
4 0

This doesn’t make since

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What geometric construction is shown below
AnnyKZ [126]

Answer:

doubling the square Apex

Step-by-step explanation:

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3 years ago
Donna was playing a trivia game where you gained points for correct answers and lost points for incorrect answers. At the start
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Step-by-step explanation:

B 100

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2 years ago
Read 2 more answers
X
12345 [234]

Answer: 28.35\ minutes

Step-by-step explanation:

Let be "x" the time in minutes a 150-pound person must walk at  4 mph to use at least 190 calories.

 The amount of calories that a 150-pound person uses  in 1 minute when walking at a speed of 4 mph is:

Calories\ per\ minute=6.7

Therefore, knowing this, we can write the following proportion:

\frac{1}{6.7}=\frac{x}{190}

Finally, we must solve for "x" in order to find its value.

Multiplying both sides of the equation by 190, we get this result:

(190)(\frac{1}{6.7})=(\frac{x}{190})(190)\\\\x=28.35

3 0
3 years ago
Find a solution x = x(t) of the equation x′ + 2x = t2 + 4t + 7 in the form of a quadratic function of t, that is, of the form x(
Temka [501]
The particular quadratic solution to the ODE is found as follows:

x=at^2+bt+c
x'=2at+b

(2at+b)+2(at^2+bt+c)=t^2+4t+7
2at^2+(2a+2b)t+(b+2c)=t^2+4t+7

\begin{cases}2a=1\\2(a+b)=4\\b+2c=7\end{cases}\implies a=\dfrac12,b=\dfrac32,c=\dfrac{11}4

Note that there's also the fundamental solution to account for, which is obtained from the characteristic equation for the ODE:

x'+2x=0\implies r+2=0\implies r=-2

so that x_c=Ce^{-2t} is a characteristic solution to the ODE, and the general solution would be

x=Ce^{-2t}+\dfrac{t^2}2+\dfrac{3t}2+\dfrac{11}4
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3 years ago
Selene's checking account balance was -$30, and then she withdrew $40 more. What is her checking account balance after the withd
irakobra [83]
-$70 is her balance after withdrawing the forty dollars
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3 years ago
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