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Mariulka [41]
3 years ago
15

Can someone please help me?

Mathematics
1 answer:
Natali [406]3 years ago
7 0

Answer:

1. 35/12

2. 23/10

3. 3/4

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Answer:

The rate at which the distance between the two people is changing 15 seconds later is 7.28 ft/sec.

Step-by-step explanation:

Here, we note the following

Let the person walking way fom the elevator be X

Let the other person going up in the elevator be Y

Therefore after 15 seconds, their positions will be;

For X,  2 ft/sec × 15 s = 30 ft away from the elevator

For Y,  7 ft/sec × 15 s = 105 ft up in the elevator

At that instant, the distance between them is given as

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d = √11925 ft²  = 109.202 ft

The rate of change of the distance between the two peopl, X and Y is given as

\frac{dd^2}{dt} = \frac{dx^2}{dt} + \frac{dy^2}{dt}

Therefore,  2d\frac{dd}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt} or d\frac{dd}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}

Since \frac{dx}{dt} is given as 2 ft/sec and \frac{dy}{dt} = 7 ft/sec

Then  d\frac{dd}{dt} = 30 \times 2 + 105 \times 7 = 795\\

\frac{dd}{dt} = \frac{795}{109.202 } =7.28 ft/sec

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