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trapecia [35]
3 years ago
12

37. Simplify to find x: 3-(4 X 3) = x (483) - 7

Mathematics
1 answer:
MariettaO [177]3 years ago
5 0

Answer:

-0.003 x 2+.195 x -.483=0.  -0.003x^2+.195x-.483=0     2,3,3,3,5,3,2,3,

Prime factors. 1000,200,1000

square root of (x-(65/2))2 is (x-(65/2))2/2 = (x-(65/2))1 = x-(65/2)

Step-by-step explanation:

−0.003 x 2+.195 x −.483=0. Enter an ... -0.003x^2+.195x-.483=0 ... {Left,Right}. 2, 3, 3, 3. 5, 3, 2, 3. Product of all. Prime Factors, 1000, 200, 1000 ... Step 7 : ... Note that the square root of (x-(65/2))2 is (x-(65/2))2/2 = (x-(65/2))1 = x-(65/2)

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An electrician charges a base fee of $70 plus $45 for each hour of work. The minimum the electrician charges is $160. Create a t
Murrr4er [49]

Answer:

1) See below for table.

2) Domain: \{1, 2, 3, 4\}

Range: \{160, 160, 205, 250\}

Yes, this is a function.

Step-by-step explanation:

We know that the electrician charges a base fee of $70 plus $45 for each hour of work.

We also know that the minimum the electrician charges is $160.

Let's write an equation. Let x denote the number of hours worked and y denote the total price. There's also a base fee of $70. So, we can write the following equation:

y=45x+75

Part 1)

Let's create our table for 1, 2, 3, and 4 hours. To do so, we simply need to substitute each value for x in our equation.

1 Hour:

We have:

y_1=45(1)+70

Multiply and add:

y_1=45+70=\$115

However, notice that the minimum the electrician charges is $160. Therefore, for one hour of work, the electrician will <em>still </em>charge $160. So:

y_1=\$160

2 Hours:

Substitute 2 for x:

y_2=45(2)+70=90+70=\$160\\

So:

y_2=\$160

3 Hours:

Substitute 3 for x:

y_3=45(3)+70=135+70=\$205

So:

y_3=\$205

4 Hours:

Substitute 4 for x:

y_4=45(4)+70=180+70=\$250

So:

y_4=\$ 250

Therefore, for 1, 2, 3, and 4 hours of work, the prices will be $160, $160, $205, and $250, respectively.

We can create the following table (please scroll down to see the table. Also, y is measured in dollars).

Part 2)

The domain of a relation are the input values.

In this context, our input values are the amount of hours worked, and we calculated for 1, 2, 3, and 4 hours of work.

Therefore, our domain in this context is:

\{1, 2, 3, 4\}

The range of a relation are the output values.

In this context, the output values are the price for x hours of work.

Therefore, our range in this context is:

\{160, 160, 205, 250\}

This relation <em>does</em> represent a function. Remember that a function <em>cannot </em>have repeating input values. In other words, no one input can be equal to two or more different outputs. However, one <em>output</em> <em>can</em> be mapped to two or more different inputs.

For our table, none of the inputs are repeating. So, our relation <em>is</em> a function.

And we're done!

8 0
3 years ago
For babysitting, Nicole charges a flat fee of $3, plus $5 per hour. Write an equation for the cost,c, after h hours of babysitti
Elina [12.6K]

C=3+5x

C=3+5(5)

C=3+25

C=28

She will make 28$


6 0
3 years ago
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