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Xelga [282]
3 years ago
15

Find three consecutive integers whose sum is 57????

Mathematics
1 answer:
Setler79 [48]3 years ago
7 0

Answer:18 19 20

Step-by-step explanation:"Consecutive"  means that the integers will follow each other in value, for example:  1, 2, 3 or 4, 5, 6.  Also, no decimals are needed here because "integers" are whole, counting numbers. Here is the set up:   Let x= the first integer     Then    X+1= 2nd consecutive integer   and x+2= 3rd  .  

Suppose that x=1   x+1= 1+1=2   and x+2=1+2=3   However, you need specific consecutive numbers whose sum is 57.  Remember that sum means to add:

x+  (x+1)  + (x+2) = 57                 Addition of all 3 consecutive numbers   Now solve for x

                                                   and substitute into each part to come up with the three integers:

3x + 3= 57        3x=54               x=54/3  =  18            x=18,   x+1= 18+1=19      x+2=18+2=20

Check your answer:  18+19+20=57                 57=57  Check

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F(x)=-x^2+8x+15 ...?
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Here i how I would do it:<span>f(x)=−<span>x2</span>+8x+15</span>
set f(x) = 0 to find the points at which the graph crosses the x-axis. So<span>−<span>x2</span>+8x+15=0</span>
multiply through by -1<span><span>x2</span>−8x−15=0</span> <span>(x−4<span>)2</span>−31=0</span> <span>x=4±<span>31<span>−−</span>√</span></span>
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To find the coordinates of the maximum (it is maximum) of the graph, you take a look at the completed square method above. Since we multiplied through by -1, we need to multiply through by it again to get:<span>f(x)=31−(x−4<span>)2</span></span><span>
Now this is maximal when x=4, because x=4 causes -(x-4)^2 to vanish. So the coordinates of the maximum are (4,y). To find the y, simply substitute x=4 into the equation f(x) to give y = 31. So it agrees with the mighty Satellite: (4,31) is the vertex.</span>
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