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Vikki [24]
3 years ago
6

Serious answers only !

Mathematics
1 answer:
gladu [14]3 years ago
7 0

Answer:

-3 ≤ x ≤ 1

Step-by-step explanation:

Because Domain is the x-values.

The x values can only be -3 or greater and 1 or less.

I hope this is right :P

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The equation e=1200+11t represents your elevation e in feet for each minute t you hike from a trailhead. If you graphed this equ
oee [108]
The slope would represent 1200 not sure though y= mx + b
8 0
4 years ago
Find the surface area of the square pyramid 8mm 6mm
bija089 [108]

Answer:

136 mm²

Step-by-step explanation:

A=a^{2} +2a\sqrt{\frac{a^{2} }{4} } +h^{2}

A=6^{2} +2(6)\sqrt{\frac{6^{2} }{4} } +8^{2}

A=36 +12\sqrt{\frac{36 }{4} } +64

A=36 +12\sqrt{9 } +64

A=36 +12(3)+64

A=36 +36+64

A = 136

5 0
3 years ago
The weight of male american between the ages 18 to 25 is normally distributed, with mean of 162.7 lb and a standard deviation of
MArishka [77]

Answer:

218.7 lb.

Step-by-step explanation:

We have been given that the  weight of male american between the ages 18 to 25 is normally distributed, with mean of 162.7 lb and a standard deviation of 28 lb.

One definition of obesity states that a person is obese if the z-score of his or her weight is greater than 2.

We will use z-score formula to solve our given problem.

z=\frac{x-\mu}{\sigma}, where,

z=\text{ z-score},

x=\text{ Random sample-score},

\mu=\text{ Mean},

\sigma=\text{ Standard deviation}.

Upon substituting our given values in z-score formula we will get,

2=\frac{x-162.7}{28}

Now let us solve for x.

Upon multiplying both sides of our equation by 28 we will get,

2*28=\frac{x-162.7}{28}*28

56=x-162.7

Let us add 162.7 to both sides of our equation.

56+162.7=x-162.7+162.7

218.7=x

Therefore, the obesity threshold weight for a young adult American male is 218.7 pounds.

6 0
3 years ago
Read 2 more answers
Find the given limit lim(x,y)→(a,a)x4−y4x2−y2=lim(x,y)→(a,a) (x^4−y^4)/(x2−y2)= here aa is a constant. (find the limit assuming
Aliun [14]
If x\neq y, then we can write

\dfrac{x^4-y^4}{x^2-y^2}=\dfrac{(x^2-y^2)(x^2+y^2)}{x^2-y^2}=x^2+y^2

and since this is continuous for all x\neq y, the limit as (x,y)\to(a,a) will be

\displaystyle\lim_{(x,y)\to(a,a)}\frac{x^4-y^4}{x^2-y^2}=\lim_{(x,y)\to(a,a)}(x^2+y^2)=2a^2
7 0
4 years ago
I NEED HELP ASAP solve the systems of equations using elimination
Svetach [21]

━━━━━━━☆☆━━━━━━━

▹ Answer

<em>(-2, 1)</em>

▹ Step-by-Step Explanation

4x + 3y = -5

-2x + 2y = 6

4x + 3y = -5

x = -3 + y

4(-3 + y) + 3y = -5

y = 1

x = -3 + 1

x = -2

(x, y) = (-2, 1)

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

6 0
4 years ago
Read 2 more answers
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