Answer:
0.128 g
Explanation:
Given data:
Volume of gas = 146.7 cm³
Pressure of gas = 106.5 Kpa
Temperature of gas = 167°C
Mass of oxygen gas = ?
Solution:
Volume of gas = 146.7 cm³ (146.7 /1000 = 0.1467 L)
Pressure of gas = 106.5 Kpa (106.5/101 = 1.1 atm)
Temperature of gas = 167°C (167 +273.15 = 440.15 K)
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1.1 atm× 0.1467 L / 0.0821 atm.L/ mol.K × 440.15 K
n = 0.1614 / 36.14 /mol
n = 0.004 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 0.004 mol × 32 g/mol
Mass = 0.128 g
Answer: Set with equal densities are:
15.2 g copper and 50.0 g copper ; 11.2 g gold and 14.9 g gold
Explanation:
Density is defined as mass of the substance present in unit volume of the substance.
It is an intensive property which means that two different masses of same substance will have same value of density under same conditions.
So, from the given samples with equal density are:
- 15.2 g copper and 50.0 g copper will have the same value density.
- 11.2 g gold and 14.9 g gold will have the same value density.
<h3><u>Answer and explanation</u>;</h3>
The balanced chemical equation will be;
NaHCO3 + CH3COOH = CH3COONa + H2O + CO2
After balancing the chemical equation the number of atoms of each element is the same on the reactants and on the products side.
Sodium atoms - 1
Hydrogen atoms - 5
Carbon atoms - 3
Oxygen atoms - 5
Answer:
i can't see the image so sorry
Explanation:
i couldnt see the imagee
Answer:
Precipitation reactions are ones in which at least one of the reactants is in the aqueous phase (i.e., dissolved in water), and a solid forms on the product side which was not present on the reactant side. If all the reactants are solid, then a solid product forming should not be called a precipitate. To be called a precipitate, an insoluble product must form from within solution, either from a solid and solute interacting, or from an interaction strictly between solutes.
Explanation:
