Calculate the volume of helium gas sample that has a mass of 1.2 g at room conditions

joja [24]

Answer:

Clayey soil is rich in humus and very fertile, so it is suitable for growing cereals like wheat and gram. Such soil is good at retaining water.Clayey is known to be useful for crops. Because the particle size in this soil is very fine, it has the ability to retain more amounts of water. - This makes it easy for crops to access water as it is very essential for the growth of the plant. - Some of the crops need a high amount of water in order to grow.Clayey soil is made up of fine particles that are tightly packed and increases soil density and strength. It is rich in nutrient content in the form of organic matter or humus so, it is very fertile soil. It has excellent water retaining a capacity.

7 0

2 years ago

The lock-and-key model and the induced-fit model are two models of enzyme action explaining both the specificity and the catalyt

ivolga24 [154]

Answer:

The lock-and-key model:

c. Enzyme active site has a rigid structure complementary

The induced-fit model:

a. Enzyme conformation changes when it binds the substrate so the active site fits the substrate.

Common to both The lock-and-key model and The induced-fit model:

b. Substrate binds to the enzyme at the active site, forming an enzyme-substrate complex.

d. Substrate binds to the enzyme through non-covalent interactions

Explanation:

Generally, the catalytic power of enzymes are due to transient covalent bonds formed between an enzyme's catalytic functional group and a substrate as well as non-covalent interactions between substrate and enzyme which lowers the activation energy of the reaction. This applies to both the lock-and-key model as well as induced-fit mode of enzyme catalysis.

The lock and key model of enzyme catalysis and specificity proposes that enzymes are structurally complementary to their substrates such that they fit like a lock and key. This complementary nature of the enzyme and its substrates ensures that only a substrate that is complementary to the enzyme's active site can bind to it for catalysis to proceed. this is known as the specificity of an enzyme to a particular substrate.

The induced-fit mode proposes that binding of substrate to the active site of an enzyme induces conformational changes in the enzyme which better positions various functional groups on the enzyme into the proper position to catalyse the reaction.

4 0

3 years ago

The element argon (Ar) has eight valence electrons and is a liquid at very low temperatures. Sketch a model of two argon atoms a

Romashka [77]

Larger molecules experience larger dispersion forces due to more distance of valance of electrons from the nucleus.

<h2>Cause of stronger dispersion force</h2>

Larger and heavier atoms and molecules have stronger dispersion forces than smaller and lighter ones because in a larger atom or molecule, the valence electrons are farther from the nuclei than in a smaller atom or molecule.

They are less tightly held to the nuclear charge present in the nucleus and can easily form temporary dipoles so we can conclude that larger molecules experience larger dispersion forces due to more distance of valance of electrons from the nucleus.

Learn more about London dispersion force here: brainly.com/question/1454795

Learn more: brainly.com/question/26139894

3 0

3 years ago

A mixture is made by combining 1.62 lb of salt and 5.20 lb of water.

WINSTONCH [101]

Answer:

23.8

Explanation:

Formula

weight % = weight of solute/ weight of solution x 100

weight of solution = weight of salt + weight of water

weight of solution = 1.62 lb + 5.20 lb = 6.82 lb

weight % = 1.62 / 6,82 x 100

weight % = 0.238 x 100

weight % = 23.8

4 0

3 years ago

Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride and iron. A mixtur

yuradex [85]

<u>Answer:</u> The limiting reactant is magnesium and mass of excess reactant present in the vessel is 96.35 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

<u>For magnesium:</u>

Given mass of magnesium = 41.0 g

Molar mass of magnesium = 24 g/mol

Putting values in equation 1, we get:

$\text{Moles of magnesium}=\frac{41.0g}{24g/mol}=1.708mol$

<u>For iron(III) chloride:</u>

Given mass of iron(III) chloride = 175.0 g

Molar mass of iron(III) chloride = 162.2 g/mol

Putting values in equation 1, we get:

$\text{Moles of iron(III) chloride}=\frac{175g}{162.2g/mol}=1.708mol$

The chemical equation for the reaction of magnesium and iron(III) chloride follows:

$3Mg+2FeCl_3\rightarrow 3MgCl_2+2Fe$

By Stoichiometry of the reaction:

3 moles of magnesium reacts with 2 moles of iron(III) chloride

So, 1.708 moles of magnesium will react with = $\frac{2}{3}\times 1.708=1.114mol$ of iron(III) chloride

As, given amount of iron(III) chloride is more than the required amount. So, it is considered as an excess reagent.

Thus, magnesium is considered as a limiting reagent because it limits the formation of product.

Moles of excess reactant left (iron(III) chloride) = [1.708 - 1.114] = 0.594 moles

Now, calculating the mass of iron(III) chloride from equation 1, we get:

Molar mass of iron(III) chloride = 162.2 g/mol

Moles of iron(III) chloride = 0.594 moles

Putting values in equation 1, we get:

$0.594mol=\frac{\text{Mass of iron(III) chloride}}{162.2g/mol}\\\\\text{Mass of iron(III) chloride}=(0.594mol\times 162.2g/mol)=96.35g$

Hence, the limiting reactant is magnesium and mass of excess reactant present in the vessel is 96.35 grams.

6 0

3 years ago