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RideAnS [48]
3 years ago
15

Part C. Cindy also wants to buy some plants for her garden. She has at most $30 to spend on the plants. She buys 6 tomato plants

for $12, and she wants to spend the rest of her money on herb plants. Each herb plant costs $2.75. Write an inequality for the number of herb plants Cindy can buy. Let h represent the cost of each herb plant.
Solve your inequality to find the greatest number of herb plants Cindy can buy with the money she has to spend.
Mathematics
2 answers:
hoa [83]3 years ago
6 0

Answer:

i dunoo

Step-by-step explanation:

Verizon [17]3 years ago
6 0

Answer:

12 + 2.75h ≠ 30

Or

31.26 ≠ 30

Step-by-step explanation:

12 + 2.75h = 30

We want to single out the variable so subtract 12 from both sides.

12 + 2.75h = 30

-12 -12

Now we can move down the number and then divide.

12 + 2.75h = 30

-12 -12

2.75h = 18

h ≠ 6.54545454(A repeating number.)

Since this is a repeating number we’ll take the whole number and multiply it by 2.75. Then we’ll add the 12 and compare.

2.75 x 6 = 16.5 + 12 = 28.5 < 30

28.5 is less than 30 so this is true correct answer. See what happens when you add another 2.75.

28.5 + 2.75 = 31.25 > 30

The question says *at most* meaning it’s can be equal to or less than 30. 31.25 is great than 30 so it cannot be this number.

There’s your answer.

Either 12 + 2.75 ≠ 30 or 31.25 ≠ 30

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Solution: The given random experiment follows Binomial distribution with n=10,p=0.44

Let X be the number of adults who use their smartphones in meetings or classes.

Therefore, we have to find:

P(X

We know the binomial model is:

P(X=x)=\binom{n}{x} p^{x} (1-p)^{n-x}

\therefore P(X

                       =\binom{10}{0}0.44^{0}(1-0.44)^{12-0}+\binom{10}{1}0.44^{1}(1-0.44)^{10-1}+\binom{10}{2}0.44^{2}(1-0.44)^{10-2}

                       =1 \times 1 \times 0.0030 + 10 \times 0.44 \times 0.0054 + 45 \times 0.1936 \times 0.009672

                       =0.0030+0.0238+0.0843

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Therefore, the probability that fewer than 3 of them is 0.1111

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3 years ago
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