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Ierofanga [76]
3 years ago
11

Help ASAP WILL MARK BRAINLIEST THANK YOU!

Mathematics
2 answers:
mafiozo [28]3 years ago
7 0

Answer:

○ D. (42 ÷ 2) + 5

Step-by-step explanation:

<em>Five</em> <em>more</em><em> </em><em>than</em><em> </em><em>half</em><em> </em>tells it all. He 42 miles on Monday, then drove <em>5 more than half</em>:

(42 ÷ 2) + 5

<em>Half</em><em> </em>means you either multiply by ½, or divide by 2.

I am joyous to assist you anytime.

Yuki888 [10]3 years ago
5 0

Answer:

D

Step-by-step explanation:

half of the miles he drove yesterday is <u>(42/2)</u> and <u>+5 </u>because he said five more than half.

hope this helps and is correct!

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2 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

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