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3 years ago

Which is equivalent to 2.3(-2x + 9.1) + 9(3.4x - 8)?

Mathematics

1 answer:

Rainbow [258]3 years ago

4 0

The answer is a I did the math trust me

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1/3 of the viewers opening rated the movie as goo and very good. 35 people rated it good and 20 people rated it very good. what

mylen [45]

Since a total of 55 people rated it good/very good, we know that 1/3 of the viewers are 55 people. So we can set the equation: 1/3x=55

Now, just multiply both sides by 3 (or divide by 1/3, same thing) and get your answer!

4 0

3 years ago

Jeff's math grade is based on two quizzes, two tests, and one project. The table shows Jeff’s scores on these items, as well as

vazorg [7]

Answer:

Step-by-step explanation:

If you can post the table then I'lI be happy to help

6 0

3 years ago

Read 2 more answers

Find the arc length and area of a sector with radius R =60 inches and central angle equals 30° round your answer to the nearest

Black_prince [1.1K]

Answer:

(a)31.42 inches

(b)942.48 Square Inches

Step-by-step explanation:

Given a sector of a circle with the following dimensions:

Radius of the circle =60 inches

Central Angle of the sector =30°

(a)Arc Length

Arc Length $=\dfrac{\theta}{360^\circ}X2\pi r$

$=\dfrac{30}{360^\circ}X2*60*\pi\\\\=10\pi\\\\=31.42$ Inches (correct to the nearest hundredth)$

(b)Area of the sector

Area of the sector $=\dfrac{\theta}{360^\circ}X\pi r^2$

$=\dfrac{30}{360^\circ}X\pi*60^2\\\\=300\pi\\\\=942.48$ Square Inches (correct to the nearest hundredth)$

3 0

3 years ago

Read 2 more answers

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

7 0

3 years ago

If you can help press on this

GenaCL600 [577]

It is rational because any number that can be represented in a fraction is rational. 4/33 is a fraction, so it is rational.

8 0

3 years ago