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3 years ago

9

the play began at 7:30p.m and included two 20 minute intermissions if the play lasts 2 hours and 35 minutes at what time did the

play end

2 answers:

lord [1]3 years ago

5 0

20×2=40 min

7:30+40 min= 8:10

8:10+2:35= 10:45 pm

Lady bird [3.3K]3 years ago

3 0

Answer: 10:45 p.m

Solution: Add 7:30 + 2 hours = 8:30
Then Add 35 minuets = 9:05
Then 2 twenty minute intermissions = 10:45

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The angle measures associated with which set of ordered pairs share the same reference angle? (Negative StartFraction StartRoot

Katarina [22]

Answer:

$(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)$

Step-by-step explanation:

The reference angle is the angle that the given angle makes with the x-axis.

For an ordered pair to share the same reference angle, the x and y coordinates must be the same or a factor of each other.

From the given options:

$(A)\left(-\dfrac{\sqrt{3} }{2} ,-\dfrac{1 }{2}\right)$ and \left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)\\\\(B)\left(\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(-\dfrac{\sqrt{3} }{2}, \dfrac{1 }{2}\right)\\\\(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)\\\\(D)\left(\dfrac{\sqrt{3} }{2},\dfrac{1 }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)$

We observe that only the pair in option C has the same x and y coordinate with the second set of points being a negative factor of the first term. Therefore, they have the same reference angle.

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3 years ago

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The booster club will sell raffle tickets to raise money for new band uniforms. The total cost of the uniforms is $16,272. Each

Zina [86]

Answer: 1,356 tickets

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divide by 12 on both sides

12x÷12=16,272÷12

x=16,272÷12

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I hope this is good enough:

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3 years ago

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SAS

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2 years ago

Y=5x+2 <br> 4x-y=0<br> is (2,12) a solution of the system?

Svetach [21]

Answer:

The point (2,12) is not a solution of the system

see the explanation

Step-by-step explanation:

we have

$y=5x+2$ ----> equation A

$4x-y=0$ ----> equation B

Solve the system by elimination

Adds equation A and equation B

$y=5x+2\\4x-y=0\\------\\y+4x-y=5x+2+0\\4x=5x+2\\5x-4x=-2\\x=-2$

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therefore

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