While I'm unsure what the word choices were, his claim is likely to be true.
Since he claims the probability of heads is 40%, that should be what we see in an experiment. 0.38 is very close to 0.40, or 40%, so this is true. Therefore his claim is likely to be true, and the probability of tails should be about 60%.
Answer:
15x^2-3x-1
Step-by-step explanation:
All we have to do is collect like terms and calculate! Hope this helps!
Answer:
r = 4.5%
Step-by-step explanation:
Formula:
I = Prt
r = I/(Pt)
Given:
I = 662.29
P = 4205
t = 3.5
Work:
r = I/(Pt)
r = 662.29/(4205 * 3.5)
r = 662.29/14717.5
r = 0.045
r = 4.5%
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

Multiply both sides by <em>r</em> :

Subtract the latter sum from the first, which eliminates all but the first and last terms:

Solve for
:

Then as gets arbitrarily large, the term
will converge to 0, leaving us with

So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18