I need help figuring out what goes into the boxes

Find the average rate of change.<br><br> p(x) = 6x + 7 on [2, 2 + h] , h ≠ 0

siniylev [52]

Answer:

6.

Step-by-step explanation:

This is [p(2+h)) - p(2) ] / ((2 + h - 2)

= [ 6(2) + h) + 7 - (6(2) + 7)] / h

= ( 12 + 6h + 7 - 12 - 7) / h

= 6h / h

= 6.

4 0

3 years ago

I need question a and b done pls help

FrozenT [24]

Answer:

A. 5

B. 12

Step-by-step explanation:

What you do is you substitute -2 into the a and the 3 into the b.

a. 3(-2)^2-5(3)+8 b. 2/3(3)-5(-2)

3(4)-15+8 2-(-10)

12-15+8 12 is your answer.

-3+8

5 is your answer.

8 0

3 years ago

Read 2 more answers

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

Marianna is painting a ramp for the school play in the shape of a right triangular prism. The ramp has dimensions as shown below

garri49 [273]

32 and 44 I hope I got it right

6 0

3 years ago

Which of the following is equivalent to 60 g?

guajiro [1.7K]

Answer:

The number of cups that are equivalent to 60 grams varies based on what is being measured.

Step-by-step explanation:

j

5 0

3 years ago

I need help figuring out what goes into the boxes​

I need help figuring out what goes into the boxes